Werner's theory of coordination compounds


Werner's Theory of Coordination Compounds

1. Definition and Core Explanation

Werner's theory of coordination compounds, proposed by the Swiss chemist Alfred Werner in 1893, was the first successful explanation of the structure and bonding in coordination compounds. According to Werner’s theory, coordination compounds consist of a central metal atom or ion surrounded by molecules or ions called ligands. Werner’s theory distinguishes between two types of valencies: primary valency and secondary valency.

 

- Primary Valency: Refers to the oxidation state of the metal and is typically satisfied by anions.

- Secondary Valency: Represents the coordination number, which is the number of ligands attached to the central metal ion. This valency is directional and determines the spatial arrangement of ligands around the metal ion.

 

Werner’s theory successfully explained the structures of coordination compounds, including their spatial arrangements and the phenomenon of isomerism in coordination complexes.

2. Key Postulates of Werner's Theory

 

1. Primary and Secondary Valencies:

   - The primary valency corresponds to the oxidation state and is satisfied by ionic bonding with counter ions.

   - The secondary valency refers to the coordination number, satisfied by the bonding of ligands to the metal ion.

 

2. Directional Nature of Secondary Valency:

   - The secondary valency is fixed for a given metal ion and determines the geometric structure of the compound, such as octahedral, tetrahedral, or square planar.

 

3. Coordination Number:

   - Each metal ion has a characteristic coordination number (secondary valency), typically ranging from 2 to 6, depending on the metal ion and the ligands.

 

4. Isomerism:

   - Werner’s theory explains the existence of isomers in coordination compounds, as different spatial arrangements of ligands can lead to different structures with the same chemical formula.

3. Key Terms and Concepts

- Primary Valency: The oxidation state of the metal ion, satisfied by ionic bonds with anions.

- Secondary Valency: The coordination number, representing the number of ligands attached to the metal ion, satisfied by coordinate covalent bonds.

- Ligands: Molecules or ions that donate electron pairs to the central metal ion to form coordination bonds.

- Coordination Number: The number of ligands attached to the central metal ion, determining the geometry of the complex.

4. Important Rules, Theorems, and Principles

- Werner’s Postulates on Valency: Differentiates between primary (oxidation state) and secondary (coordination number) valencies, establishing a foundation for understanding coordination complexes.

- Coordination Geometry: Based on the secondary valency, different geometries are possible, such as octahedral (coordination number 6) and tetrahedral (coordination number 4).

5. Illustrative Diagrams and Visuals

 

1. Structure of [Co(NH\(_3\))\(_6\)]Cl\(_3\):

   - Diagram showing the coordination of six NH\(_3\) ligands around a central Co\(^{3+}\) ion, forming an octahedral structure.

 

2. Primary and Secondary Valency Representation:

   - Illustration distinguishing primary valency (satisfied by Cl\(^-\) ions) and secondary valency (satisfied by NH\(_3\) ligands) in [Co(NH\(_3\))\(_6\)]Cl\(_3\).

 

[Include visuals like structural diagrams of coordination compounds to illustrate primary and secondary valency concepts.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Explain the primary and secondary valencies of [Co(NH\(_3\))\(_6\)]Cl\(_3\).

 

- Solution:

  1. Primary Valency: The primary valency of Co in [Co(NH\(_3\))\(_6\)]Cl\(_3\) is +3, satisfied by three Cl\(^-\) ions.

  2. Secondary Valency: The secondary valency (coordination number) is 6, as six NH\(_3\) molecules coordinate with the Co\(^{3+}\) ion.

  - Answer: In [Co(NH\(_3\))\(_6\)]Cl\(_3\), the primary valency is +3, and the secondary valency is 6.

 

Example Problem 2: Why do coordination compounds like [Pt(NH\(_3\))\(_4\)]Cl\(_2\) exhibit specific geometries?

 

- Solution:

  1. Coordination Number and Geometry: The secondary valency (coordination number) of Pt in [Pt(NH\(_3\))\(_4\)]Cl\(_2\) is 4, which corresponds to a square planar geometry.

  2. Directional Bonding: The secondary valency is directional, leading to specific spatial arrangements of ligands.

  - Answer: [Pt(NH\(_3\))\(_4\)]Cl\(_2\) has a square planar geometry due to the coordination number of 4, determined by Werner’s theory.

7. Common Tricks, Shortcuts, and Solving Techniques

- Identify Primary and Secondary Valencies: Use the formula of the coordination compound to distinguish between primary (oxidation state) and secondary (coordination number) valencies.

- Determine Geometry Based on Coordination Number: The coordination number can help predict the geometry (e.g., 4 = tetrahedral or square planar, 6 = octahedral).

8. Patterns in JEE Questions

JEE Advanced questions on Werner’s theory may involve:

- Identifying primary and secondary valencies in coordination compounds.

- Predicting the geometry of coordination complexes based on the coordination number.

- Explaining the difference between ionic and coordinate covalent bonds in coordination compounds.

9. Tips to Avoid Common Mistakes

- Confusing Primary and Secondary Valency: Remember that primary valency relates to oxidation state, while secondary valency relates to the number of ligands (coordination number).

- Incorrectly Predicting Geometry: Ensure that the coordination number is correctly interpreted to predict the compound's geometry.

10. Key Points to Remember for Revision

- Primary vs. Secondary Valency: Primary valency corresponds to oxidation state; secondary valency corresponds to coordination number.

- Geometry Based on Coordination Number: Common geometries include octahedral (6 ligands), tetrahedral (4 ligands), and square planar (4 ligands with specific ligands).

- Werner’s Theory: Provides foundational principles to understand bonding and structure in coordination compounds.

11. Real-World Applications and Cross-Chapter Links

- Medicinal Chemistry: Coordination compounds play crucial roles in medicine, such as in chemotherapy drugs like cisplatin.

- Industrial Catalysts: Many coordination compounds act as catalysts due to their specific geometries and electron-donating ligands.

- Cross-Concept Connections: Links to oxidation states, bonding theories, and molecular geometry in coordination chemistry.

Questions

Q 1. According to the postulates of Werner for coordination compounds;

(a) primary valency is ionizable;

(b) secondary valency is ionizable;

(c) primary and secondary valencies are non-ionizable;

(d) only primary valency is non-ionizable.;

Primary and secondary valency in coordination compounds


Primary and Secondary Valency in Coordination Compounds

1. Definition and Core Explanation

In coordination compounds, the central metal ion can exhibit two types of valencies, known as primary valency and secondary valency. This concept was introduced by Alfred Werner in his theory of coordination compounds, which explains the bonding and structure of these compounds.

 

- Primary Valency: This valency corresponds to the oxidation state of the metal ion and is typically satisfied by anions. It represents the ionic bonding nature of the compound and is often ionizable in solution.

- Secondary Valency: This valency is associated with the coordination number of the metal ion, which is the number of ligands directly bonded to the metal ion. The secondary valency is satisfied by coordinate covalent bonds and is not ionizable.

 

In essence, primary valency reflects the charge balance in the compound, while secondary valency determines the number of ligands attached to the metal, affecting the geometry of the compound.

2. Distinction between Primary and Secondary Valency

 

1. Primary Valency (Oxidation State):

   - Refers to the total charge or oxidation state of the central metal ion.

   - Satisfied by ions like Cl\(^-\), NO\(_3^-\), and other anions that can balance the charge of the metal.

   - These ions are usually present outside the coordination sphere and are ionizable in solution.

 

2. Secondary Valency (Coordination Number):

   - Refers to the total number of ligands directly bonded to the metal ion.

   - Satisfied by ligands that donate electron pairs to the metal ion to form coordinate covalent bonds.

   - The secondary valency is fixed for a given metal ion and defines the geometry of the coordination complex (e.g., octahedral, tetrahedral).

 

For example, in [Co(NH\(_3\))\(_6\)]Cl\(_3\):

- The primary valency of Co is +3, satisfied by three Cl\(^-\) ions.

- The secondary valency is 6, as six NH\(_3\) molecules coordinate with Co\(^{3+}\).

3. Key Terms and Concepts

- Primary Valency: The oxidation state of the metal ion, represented by the charge and balanced by anions.

- Secondary Valency: The coordination number, which is the number of ligands attached to the metal ion.

- Coordination Sphere: The central metal ion and its attached ligands, enclosed in square brackets in a coordination compound’s formula.

- Ionization: Primary valency can be ionized in solution, while secondary valency typically remains non-ionizable.

4. Important Rules, Theorems, and Principles

- Werner’s Theory on Valency: Differentiates primary valency as the metal ion’s oxidation state and secondary valency as the coordination number, helping to explain the bonding and structure of coordination compounds.

- Coordination Number: Dictated by the secondary valency, which is fixed for a given metal ion and largely determines the spatial arrangement of ligands around the metal.

5. Illustrative Diagrams and Visuals

 

1. Structure of [Co(NH\(_3\))\(_6\)]Cl\(_3\):

   - Diagram showing the primary valency (Cl\(^-\) ions) outside the coordination sphere and the secondary valency (NH\(_3\) ligands) inside the coordination sphere.

 

2. Primary vs. Secondary Valency Representation:

   - Illustration distinguishing primary and secondary valency with examples of how different ions and ligands satisfy these valencies in coordination compounds.

 

[Include visuals like the structural diagram of [Co(NH\(_3\))\(_6\)]Cl\(_3\) to show the primary and secondary valencies.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Determine the primary and secondary valencies of the metal ion in [Cr(NH\(_3\))\(_4\)Cl\(_2\)]Cl.

 

- Solution:

  1. Primary Valency: Chromium’s primary valency is +3, satisfied by one Cl\(^-\) ion outside the coordination sphere.

  2. Secondary Valency: The coordination number (secondary valency) is 6, satisfied by four NH\(_3\) molecules and two Cl\(^-\) ions within the coordination sphere.

  - Answer: Primary valency is +3, and secondary valency (coordination number) is 6.

 

Example Problem 2: Explain why [Pt(NH\(_3\))\(_4\)]Cl\(_2\) has a primary valency of +2 and a secondary valency of 4.

 

- Solution:

  1. Primary Valency: The primary valency of Pt is +2, satisfied by two Cl\(^-\) ions outside the coordination sphere.

  2. Secondary Valency: The coordination number is 4, fulfilled by four NH\(_3\) ligands attached to Pt in a square planar arrangement.

  - Answer: Primary valency is +2 (balanced by two Cl\(^-\)), and secondary valency is 4 (fulfilled by four NH\(_3\) ligands).

7. Common Tricks, Shortcuts, and Solving Techniques

- Identifying Primary Valency: Look for the ions outside the coordination sphere (often anions) to determine the primary valency.

- Determining Secondary Valency: Count the ligands within the coordination sphere to identify the secondary valency or coordination number.

8. Patterns in JEE Questions

JEE Advanced questions on primary and secondary valency may involve:

- Determining the primary and secondary valencies of a given coordination compound.

- Predicting ionizable ions based on the primary valency.

- Explaining the role of coordination number in determining the structure of coordination compounds.

9. Tips to Avoid Common Mistakes

- Confusing Primary and Secondary Valency: Primary valency relates to the oxidation state and is ionizable, while secondary valency relates to coordination number and is non-ionizable.

- Overlooking Coordination Number in Geometry: The secondary valency (coordination number) determines the geometry of the complex, so count ligands carefully.

10. Key Points to Remember for Revision

- Primary Valency (Oxidation State): Typically satisfied by ionizable anions outside the coordination sphere.

- Secondary Valency (Coordination Number): Satisfied by ligands attached directly to the metal ion, determining the geometry of the coordination compound.

- Werner’s Theory on Valency: Differentiates primary and secondary valencies, laying the foundation for understanding coordination chemistry.

11. Real-World Applications and Cross-Chapter Links

- Medicinal Applications: Coordination compounds with specific primary and secondary valencies are used in drugs for cancer treatment, such as cisplatin.

- Industrial Catalysts: Coordination compounds serve as catalysts in reactions, where primary and secondary valencies dictate stability and reactivity.

- Cross-Concept Connections: Links to oxidation states, bonding theories, and molecular geometry in coordination chemistry.

Questions

Q 1. Which of the following postulates of Werner's theory is incorrect?;

(a) Primary valencies are satisfied by negative ions.;

(b) Secondary valencies are satisfied by neutral molecules or negative ions.;

(c) Secondary valence is equal to the coordination number and it depends upon the nature of ligand attached to metal.;

(d) The ions/ groups bound by the secondary linkages to the metal have charecteristic spatial arrangements.;

Primary valency and oxidation states in coordination complexes


Primary Valency and Oxidation States in Coordination Complexes

1. Definition and Core Explanation

In coordination complexes, the primary valency is related to the oxidation state of the central metal ion. The primary valency represents the total charge on the metal ion, which is typically satisfied by anions outside the coordination sphere. This concept is foundational to understanding the charge balance within coordination compounds, as well as predicting their behavior in solution.

 

- Primary Valency: The primary valency is the oxidation state of the metal ion and is often balanced by anions that can dissociate in solution. For example, in [Co(NH\(_3\))\(_6\)]Cl\(_3\), the primary valency of cobalt is +3, which is balanced by three Cl\(^-\) ions.

- Oxidation State: The oxidation state indicates the charge on the metal after accounting for the charges of all ligands and counter ions. It helps determine the overall charge of the coordination complex.

 

Understanding the primary valency and oxidation state is essential in predicting the compound’s reactivity, stability, and overall charge in different chemical environments.

2. Determining Primary Valency and Oxidation States

 

1. Primary Valency Calculation:

   - The primary valency (oxidation state) of the metal is determined by considering the charge on the metal and the charges of any counter ions outside the coordination sphere.

   - For example, in [Pt(NH\(_3\))\(_4\)]Cl\(_2\), platinum’s primary valency is +2, as it is balanced by two Cl\(^-\) ions outside the coordination sphere.

 

2. Oxidation State Determination:

   - The oxidation state of the metal ion in a coordination complex is calculated by balancing the charges of the metal, ligands, and any counter ions.

   - In the example of [CoCl\(_3\)(NH\(_3\))\(_3\)], cobalt has an oxidation state of +3, with three chloride ions and three neutral ammonia molecules coordinated to it.

 

The primary valency, expressed as the oxidation state, directly influences the metal’s chemical reactivity, ligand interactions, and stability in a coordination complex.

 

3. Key Terms and Concepts

- Primary Valency: The oxidation state or charge of the central metal ion, balanced by counter ions.

- Oxidation State: The charge on the central metal ion after accounting for the charges of all ligands and any external anions or cations.

- Counter Ions: Ions outside the coordination sphere that balance the primary valency and may dissociate in solution.

- Coordination Sphere: The central metal ion and its bonded ligands, often enclosed in square brackets.

4. Important Rules, Theorems, and Principles

- Oxidation State Assignment: The sum of the charges on the central metal ion and the ligands inside the coordination sphere must balance with any external ions to maintain electrical neutrality.

- Werner’s Principle of Primary Valency: According to Werner’s theory, primary valency corresponds to the oxidation state and determines the type and number of anions required to balance the charge.

5. Illustrative Diagrams and Visuals

 

1. Oxidation State Calculation for [Co(NH\(_3\))\(_6\)]Cl\(_3\):

   - Diagram showing the coordination sphere with six NH\(_3\) molecules around Co\(^{3+}\) and three Cl\(^-\) ions outside, demonstrating the primary valency of +3.

 

2. Primary Valency and Coordination Sphere Representation:

   - Illustration of primary valency as the oxidation state and secondary valency as the coordination number, with examples like [Pt(NH\(_3\))\(_4\)]Cl\(_2\).

 

[Include visuals like structural diagrams to represent primary valency and oxidation state with specific examples.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Determine the oxidation state of the metal ion in [Fe(CN)\(_6\)]\(^{4-}\).

 

- Solution:

  1. Identify Ligands: The CN ligand has a charge of -1.

  2. Set Up the Equation: Let the oxidation state of Fe be \(x\).

     - \(x + 6(-1) = -4\)

  3. Solve for \(x\): \(x = +2\).

  - Answer: The oxidation state of Fe in [Fe(CN)\(_6\)]\(^{4-}\) is +2.

 

Example Problem 2: Calculate the primary valency of chromium in [Cr(H\(_2\)O)\(_4\)(Cl)\(_2\)]Cl.

 

- Solution:

  1. Identify Ligands: Water (H\(_2\)O) is neutral, and each chloride ion (Cl\(^-\)) has a charge of -1.

  2. Set Up the Equation: Let the oxidation state of Cr be \(x\).

     - \(x + 2(-1) = +1\) (since there is one Cl\(^-\) outside the coordination sphere).

  3. Solve for \(x\): \(x = +3\).

  - Answer: The primary valency (oxidation state) of Cr in [Cr(H\(_2\)O)\(_4\)(Cl)\(_2\)]Cl is +3.

7. Common Tricks, Shortcuts, and Solving Techniques

- Counting Ligand Charges: For oxidation state calculations, sum up the charges of the ligands inside the coordination sphere and equate with the complex’s overall charge.

- Identify Counter Ions: Use counter ions outside the coordination sphere to help determine the primary valency and oxidation state.

8. Patterns in JEE Questions

JEE Advanced questions on primary valency and oxidation states may involve:

- Calculating the oxidation state of a metal ion in complex ions.

- Distinguishing between primary and secondary valencies.

- Predicting the number of counter ions required to balance the primary valency.

9. Tips to Avoid Common Mistakes

- Mixing Up Ligand Charges: Be careful with ligand charges; neutral ligands like NH\(_3\) do not contribute to the oxidation state.

- Forgetting Counter Ions: Primary valency is often balanced by counter ions outside the coordination sphere, which may be omitted in formulas.

 

10. Key Points to Remember for Revision

- Primary Valency = Oxidation State: The charge on the central metal ion balanced by counter ions.

- Oxidation State Calculation: Sum of metal charge and ligand charges within the coordination sphere equals the complex’s total charge.

- Role in Stability and Reactivity: Oxidation state affects the reactivity, stability, and type of ligands that can coordinate with the metal ion.

11. Real-World Applications and Cross-Chapter Links

- Redox Reactions: Understanding oxidation states in coordination complexes is essential in redox reactions and catalysis.

- Medicinal Chemistry: Metal oxidation states are critical in drugs like cisplatin, where the oxidation state affects biological interactions.

- Cross-Concept Connections: Links to oxidation states, electron configurations, and bonding theories in transition metal chemistry.

Questions

Q 1. \(\mathrm{CrCl}_{3}\) has primary valence of;

(a) 3;

(b) 4;

(c) 2;

(d) 1;

Coordination number and structure of complexes


Coordination Number and Structure of Complexes

1. Definition and Core Explanation

The coordination number of a coordination complex is defined as the number of ligand donor atoms directly bonded to the central metal ion. This number plays a crucial role in determining the structure and geometry of the complex.

 

- Coordination Number (CN): It represents the number of coordinate covalent bonds between the central metal ion and ligands. For example, in [Co(NH\(_3\))\(_6\)]\(^{3+}\), the coordination number of Co is 6 because there are six ammonia molecules attached to it.

- Structure and Geometry: Based on the coordination number, the spatial arrangement of ligands around the metal ion can vary, leading to different geometries such as octahedral, tetrahedral, square planar, and more.

 

Common coordination numbers for transition metals range from 2 to 8, with 4 (tetrahedral or square planar) and 6 (octahedral) being the most common.

2. Common Coordination Numbers and Their Geometries

 

1. Coordination Number 2:

   - Geometry: Linear.

   - Example: [Ag(NH\(_3\))\(_2\)]\(^+\), where the silver ion is bonded to two ammonia molecules in a linear arrangement.

 

2. Coordination Number 4:

   - Geometry: Tetrahedral or square planar.

   - Examples:

     - Tetrahedral: [NiCl\(_4\)]\(^{2-}\), where nickel is bonded to four chloride ions in a tetrahedral structure.

     - Square Planar: [Pt(NH\(_3\))\(_4\)]\(^{2+}\), where platinum is bonded to four ammonia molecules in a square planar arrangement.

 

3. Coordination Number 6:

   - Geometry: Octahedral.

   - Example: [Co(NH\(_3\))\(_6\)]\(^{3+}\), where cobalt is bonded to six ammonia molecules, forming an octahedral structure.

 

4. Higher Coordination Numbers (7 and 8):

   - Geometries: Pentagonal bipyramidal, square antiprismatic.

   - Example: [Mo(CN)\(_8\)]\(^{4-}\) has a coordination number of 8 with a square antiprismatic geometry.

 

The coordination number largely depends on the size of the metal ion, the size of the ligands, and the electronic configuration of the metal ion.

3. Key Terms and Concepts

- Coordination Number (CN): The number of ligand donor atoms attached to the central metal ion.

- Ligand Geometry: The spatial arrangement of ligands around the metal ion, influenced by the coordination number.

- Tetrahedral and Octahedral Complexes: Common geometries for coordination numbers 4 and 6, respectively.

4. Important Rules, Theorems, and Principles

- Steric Effects: The size of the ligands can limit the coordination number; bulky ligands often result in lower coordination numbers due to steric hindrance.

- Crystal Field Theory: Explains the splitting of d-orbitals based on the geometry (e.g., octahedral or tetrahedral) determined by the coordination number.

5. Illustrative Diagrams and Visuals

 

1. Examples of Geometries Based on Coordination Number:

   - Diagrams illustrating linear (CN = 2), tetrahedral and square planar (CN = 4), and octahedral (CN = 6) structures.

 

2. Crystal Field Splitting in Octahedral and Tetrahedral Geometries:

   - Diagrams showing the d-orbital splitting pattern in octahedral and tetrahedral fields, correlating geometry with electronic structure.

 

[Include visuals like geometric diagrams to show coordination numbers and associated structures for clarity.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Determine the coordination number and geometry of [Fe(CN)\(_6\)]\(^{4-}\).

 

- Solution:

  1. Identify Ligands: CN\(^-\) is a monodentate ligand, with each CN\(^-\) contributing one donor atom.

  2. Calculate Coordination Number: There are six CN\(^-\) ligands, so the coordination number is 6.

  3. Determine Geometry: A coordination number of 6 typically corresponds to an octahedral geometry.

  - Answer: The coordination number of [Fe(CN)\(_6\)]\(^{4-}\) is 6, and its geometry is octahedral.

 

Example Problem 2: Explain why [PtCl\(_4\)]\(^{2-}\) has a square planar geometry instead of tetrahedral, despite having a coordination number of 4.

 

- Solution:

  1. Electronic Configuration of Pt: Platinum’s electron configuration and strong field ligands (Cl\(^-\)) favor a dsp\(^2\) hybridization.

  2. Geometry Determination: dsp\(^2\) hybridization leads to a square planar geometry rather than tetrahedral.

  - Answer: [PtCl\(_4\)]\(^{2-}\) has a square planar geometry due to dsp\(^2\) hybridization, which is favored by platinum’s electronic configuration.

7. Common Tricks, Shortcuts, and Solving Techniques

- Coordination Number and Geometry: Remember that CN = 4 can be either tetrahedral (especially with d\(^0\) or d\(^10\) metals) or square planar (especially with d\(^8\) metals like Pt\(^{2+}\)).

- Identify Ligands and Count Donor Atoms: Some ligands are polydentate and contribute more than one donor atom, which affects the coordination number.

8. Patterns in JEE Questions

JEE Advanced questions on coordination number and structure may involve:

- Determining coordination number and geometry based on the formula of the complex.

- Explaining the choice of geometry based on hybridization and ligand field strength.

- Distinguishing between possible geometries for a given coordination number.

9. Tips to Avoid Common Mistakes

- Confusing Tetrahedral and Square Planar Geometries: Coordination number 4 can lead to either geometry; consider the metal’s electronic configuration.

- Overlooking Polydentate Ligands: Ligands like ethylenediamine (en) are bidentate, which affects the coordination number calculation.

10. Key Points to Remember for Revision

- Coordination Number: Defines the number of ligand atoms directly attached to the metal ion.

- Geometry Based on CN: CN = 2 (linear), CN = 4 (tetrahedral or square planar), CN = 6 (octahedral).

- Influence of Ligands: Ligand size, charge, and field strength affect the coordination number and geometry.

11. Real-World Applications and Cross-Chapter Links

- Catalysis: The geometry of a coordination complex often affects its catalytic activity, such as in square planar platinum-based catalysts.

- Medicinal Chemistry: The geometry and coordination number in complexes like cisplatin (square planar) are crucial for its function in cancer treatment.

- Cross-Concept Connections: Links to hybridization, molecular geometry, and crystal field theory for understanding stability and reactivity.

Questions

Q 1. One mole of the complex compound \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}_{3}\), gives 3 moles of ions on dissolution in water One mole of the same complex reacts with two moles of \(\mathrm{AgNO}_{3}\) solution to yield two moles of \(\mathrm{AgCl}(\mathrm{s})\) The structure of the complex is;

(a) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right] .2 \mathrm{NH}_{3}\);

(b) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl} . \mathrm{NH}_{3}\);

(c) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}\right] \mathrm{Cl}_{2} \cdot \mathrm{NH}_{3}\);

(d) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}\);

Precipitation reactions in coordination compounds


Precipitation Reactions in Coordination Compounds

1. Definition and Core Explanation

Precipitation reactions in coordination compounds occur when an insoluble solid (precipitate) is formed by the reaction between two soluble substances. In coordination chemistry, such reactions often involve the exchange of ligands or the interaction of the coordination complex with counter ions, resulting in the formation of an insoluble complex.

 

Precipitation in Coordination Complexes:

- A coordination compound may precipitate if the newly formed complex is insoluble in the given solvent.

- Precipitation reactions are commonly used for purification, identification of metals, and synthesis of coordination complexes.

 

For example:

- When [Ag(NH\(_3\))\(_2\)]\(^+\) reacts with a chloride ion, AgCl precipitates because it is insoluble in aqueous solution.

- Similarly, addition of barium chloride (BaCl\(_2\)) to a solution containing [Fe(CN)\(_6\)]\(^{4-}\) leads to the precipitation of Ba\(_2\)[Fe(CN)\(_6\)].

2. Mechanism of Precipitation in Coordination Compounds

 

1. Ligand Exchange:

   - When a ligand in a coordination complex is replaced by another anion or ligand that forms an insoluble compound, precipitation occurs.

   - For example, in the case of [Cu(NH\(_3\))\(_4\)]SO\(_4\), if sodium hydroxide (NaOH) is added, Cu(OH)\(_2\) precipitates due to the formation of an insoluble hydroxide.

 

2. Formation of Low Solubility Compounds:

   - A coordination complex may interact with anions that reduce its solubility, leading to the precipitation of the entire compound.

   - This is often used in analytical chemistry for the selective separation and identification of metal ions.

 

3. Change in Solubility Product (K\(_{sp}\)):

   - Precipitation occurs if the product of ion concentrations exceeds the solubility product (K\(_{sp}\)) of the precipitate.

   - For instance, AgCl precipitates when silver and chloride ions are present in concentrations that exceed the K\(_{sp}\) of AgCl.

3. Key Terms and Concepts

- Precipitate: An insoluble solid formed in solution as a result of a chemical reaction.

- Ligand Exchange: Replacement of one ligand by another in a coordination complex, which can lead to precipitation.

- Solubility Product (K\(_{sp}\)): The equilibrium constant for the dissolution of a sparingly soluble compound; precipitation occurs when this value is exceeded.

- Counter Ions: Ions that balance the charge of the coordination complex but do not participate directly in bonding with the central metal ion.

4. Important Rules, Theorems, and Principles

- Common Ion Effect: The presence of a common ion can decrease the solubility of a coordination complex, leading to precipitation.

- Solubility Product Principle: Precipitation takes place if the product of the ion concentrations exceeds the K\(_{sp}\) of the potential precipitate.

5. Illustrative Diagrams and Visuals

 

1. Precipitation Reaction Example:

   - Diagram showing the precipitation of AgCl from the reaction of [Ag(NH\(_3\))\(_2\)]\(^+\) with Cl\(^-\) ions.

 

2. Mechanism of Ligand Exchange Leading to Precipitation:

   - Diagram illustrating the exchange of ligands and the resulting formation of an insoluble complex, such as the precipitation of Cu(OH)\(_2\) from [Cu(NH\(_3\))\(_4\)]\(^{2+}\).

 

[Include visuals to demonstrate ligand exchange and precipitation processes for better understanding.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Describe what happens when an aqueous solution of [Ag(NH\(_3\))\(_2\)]\(^+\) is treated with HCl.

 

- Solution:

  1. Identify Components: [Ag(NH\(_3\))\(_2\)]\(^+\) is a complex ion, and HCl dissociates into H\(^+\) and Cl\(^-\).

  2. Precipitation Reaction: The Cl\(^-\) ions react with Ag\(^+\) to form AgCl, which is insoluble in water.

  - Answer: AgCl precipitates when [Ag(NH\(_3\))\(_2\)]\(^+\) is treated with HCl.

 

Example Problem 2: What will happen if barium nitrate is added to a solution containing [Fe(CN)\(_6\)]\(^{4-}\)?

 

- Solution:

  1. Identify the Reactants: [Fe(CN)\(_6\)]\(^{4-}\) is a complex ion, and Ba\(^{2+}\) from barium nitrate can react with it.

  2. Formation of Precipitate: The Ba\(^{2+}\) ions form an insoluble compound with [Fe(CN)\(_6\)]\(^{4-}\), leading to precipitation of Ba\(_2\)[Fe(CN)\(_6\)].

  - Answer: Ba\(_2\)[Fe(CN)\(_6\)] precipitates when barium nitrate is added to the solution.

7. Common Tricks, Shortcuts, and Solving Techniques

- Use of K\(_{sp}\) to Predict Precipitation: If the ion product exceeds the K\(_{sp}\) of a compound, precipitation is likely to occur.

- Look for Common Ions: If a reaction introduces a common ion that can form a low solubility compound with the metal or ligand, precipitation may occur.

 

 8. Patterns in JEE Questions

JEE Advanced questions on precipitation reactions in coordination chemistry may involve:

- Predicting whether a precipitate will form when two solutions are mixed.

- Calculating the concentrations of ions to determine if precipitation occurs based on K\(_{sp}\).

- Describing the role of ligand exchange in precipitating coordination compounds.

9. Tips to Avoid Common Mistakes

- Ignoring Ligand Strength: Stronger ligands can sometimes prevent precipitation by forming more stable complexes, even if a precipitate is expected.

- Misinterpreting K\(_{sp}\): Ensure that you compare the ion product with K\(_{sp}\) correctly; precipitation occurs only if the ion product exceeds K\(_{sp}\).

10. Key Points to Remember for Revision

- Precipitation Mechanism: Precipitation occurs when ligand exchange or interaction with a common ion forms an insoluble complex.

- Solubility Product (K\(_{sp}\)): Precipitation is driven by the solubility product; when the product of ion concentrations exceeds K\(_{sp}\), precipitation will occur.

- Examples: [Ag(NH\(_3\))\(_2\)]\(^+\) forms AgCl upon reaction with chloride ions, and [Fe(CN)\(_6\)]\(^{4-}\) forms an insoluble barium compound when treated with barium salts.

11. Real-World Applications and Cross-Chapter Links

- Qualitative Analysis: Precipitation reactions are used in qualitative analysis to identify the presence of specific metal ions by forming characteristic precipitates.

- Purification of Complexes: Precipitation is also employed to purify metal complexes, separating them from soluble impurities.

- Cross-Concept Connections: Links to solubility equilibria, common ion effect, and ligand strength are crucial for understanding precipitation reactions in coordination chemistry.

Questions

Q 1. When \(\mathrm{AgNO}_{3}\) is added to a solution of \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}_{3}\), the precipitate of \(\mathrm{AgCl}\) shows two ionisable chloride ions This means :;

(a) Two chlorine atoms satisfy primary valency and one secondary valency;

(b) One chlorine atom satisfies primary as well as secondary valency;

(c) Three chlorine atoms satisfy primary valency;

(d) Three chlorine atoms satisfy secondary valency;

Nomenclature of coordination compounds


Nomenclature of Coordination Compounds

1. Definition and Core Explanation

Nomenclature of coordination compounds involves a systematic method for naming coordination entities to clearly convey their composition, structure, and the nature of the ligands. The IUPAC system provides standardized rules to assign names to coordination complexes to avoid ambiguity.

 

The name of a coordination compound is composed of two parts:

- Cation First, Anion Second: The cation is named first, followed by the anion, irrespective of whether the complex ion is positive or negative.

- Ligands Followed by Central Metal: Ligands are named before the central metal ion, and prefixes are used to indicate the number of each type of ligand.

2. Rules for Nomenclature of Coordination Compounds

 

1. Naming the Ligands:

   - Anionic Ligands: Named by adding the suffix `-o` to the root name (e.g., chloride becomes chloro, cyanide becomes cyano).

   - Neutral Ligands: Named as the neutral molecule (e.g., water is aqua, ammonia is ammine, carbon monoxide is carbonyl).

   - Prefixes: Use prefixes like di-, tri-, tetra-, etc., to indicate the number of ligands (e.g., tetrachloro for four chloride ions). For complex ligands, prefixes such as bis-, tris-, tetrakis- are used.

 

2. Order of Ligands:

   - Ligands are named in alphabetical order, irrespective of their charges.

 

3. Naming the Central Metal:

   - Positively Charged Complexes (Cationic Complexes): The metal is named as it appears on the periodic table. For example, iron is used for Fe.

   - Negatively Charged Complexes (Anionic Complexes): The metal name ends with the suffix `-ate` (e.g., ferrate for iron, cuprate for copper).

   - Oxidation State: The oxidation state of the metal is indicated by a Roman numeral in parentheses immediately following the metal's name (e.g., cobalt(III)).

 

4. Writing the Entire Name:

   - Cation First, Anion Second: When naming the entire compound, the cation is named first, followed by the anion. This is true regardless of whether the cation or anion is the complex ion.

 

Examples:

- [Co(NH\(_3\))\(_6\)]Cl\(_3\): Hexaamminecobalt(III) chloride.

- [PtCl\(_4\)]\(^{2-}\): Tetrachloroplatinate(II) ion.

- K\(_4\)[Fe(CN)\(_6\)]: Potassium hexacyanoferrate(II).

3. Key Terms and Concepts

- Ligands: Molecules or ions that donate electron pairs to the central metal atom/ion, such as aqua, ammine, chloro, etc.

- Central Metal Atom: The metal at the center of the coordination complex, bonded to the ligands.

- Oxidation State: The charge on the central metal atom, indicated by a Roman numeral.

- Prefixes for Ligands: Indicate the number of a particular ligand in the complex (e.g., di-, tri-, tetra-).

4. Important Rules, Theorems, and Principles

- Alphabetical Order of Ligands: Ligands are always named in alphabetical order regardless of their number or type.

- Cation First, Anion Second: The entire coordination compound's name starts with the cationic part followed by the anionic part.

- Use of Suffixes for Metals: The suffix `-ate` is used for metals in anionic complexes.

5. Illustrative Diagrams and Visuals

 

1. Nomenclature Example Diagram:

   - Diagram showing the structure of [Co(NH\(_3\))\(_4\)Cl\(_2\)]Cl with annotations indicating ligand types, central metal, and oxidation state.

 

2. Naming Steps with Examples:

   - Flowchart or diagram outlining the steps for naming coordination complexes with an example for each step.

 

[Include diagrams to demonstrate ligand naming, metal naming, and an example of a complete compound.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Name the coordination compound [Cr(H\(_2\)O)\(_4\)Cl\(_2\)]Cl.

 

- Solution:

  1. Identify Ligands: There are four water molecules (aqua) and two chloride ions (chloro) bonded to chromium.

  2. Name Ligands Alphabetically: Aqua comes before chloro.

  3. Name the Central Metal: The central metal is chromium, with an oxidation state of +3 (since the complex has an overall charge of +1 and there is one Cl\(^-\) outside).

  4. Write the Name: Tetraaquadichlorochromium(III) chloride.

  - Answer: Tetraaquadichlorochromium(III) chloride.

 

Example Problem 2: Write the IUPAC name for [Fe(CN)\(_6\)]\(^{4-}\).

 

- Solution:

  1. Identify Ligands: Six cyanide ions (cyano).

  2. Name the Central Metal: Since the complex is an anion, use the suffix `-ate`. Iron becomes ferrate.

  3. Determine Oxidation State: Let the oxidation state of Fe be \(x\).

     - \(x + 6(-1) = -4\) ⟹ \(x = +2\).

  4. Write the Name: Hexacyanoferrate(II) ion.

  - Answer: Hexacyanoferrate(II) ion.

7. Common Tricks, Shortcuts, and Solving Techniques

- Identify Ligand Type First: Determine if each ligand is anionic, neutral, or cationic, and name accordingly.

- Oxidation State Calculation: Use the charge balance to determine the oxidation state of the central metal ion before naming the complex.

- Suffix `-ate` for Anionic Complexes: Always remember to use the `-ate` suffix for metals in anionic complexes (e.g., cuprate for copper).

8. Patterns in JEE Questions

JEE Advanced questions on nomenclature of coordination compounds may involve:

- Writing the IUPAC names for given coordination compounds.

- Determining the correct structure from the given name.

- Calculating the oxidation state of the central metal ion and using it in the compound's name.

9. Tips to Avoid Common Mistakes

- Forgetting the `-ate` Suffix: When naming anionic complexes, always use the `-ate` suffix for the metal name.

- Incorrect Ligand Order: Ligands must always be named in alphabetical order, not based on their charge or number.

- Oxidation State Notation: Always use Roman numerals in parentheses for the oxidation state of the metal ion.

10. Key Points to Remember for Revision

- Order of Naming: Ligands first (alphabetically), followed by the metal.

- Oxidation State Indication: Use Roman numerals in parentheses immediately after the metal’s name.

- Anionic Complex Naming: Metals in anionic complexes take the `-ate` suffix (e.g., ferrate for iron).

11. Real-World Applications and Cross-Chapter Links

- Medicinal Applications: Naming coordination compounds like cisplatin is essential for understanding their structure and mechanism of action in medicinal chemistry.

- Industrial Catalysts: Correct naming of catalysts is crucial in industries where coordination complexes are used in processes like hydrogenation.

- Cross-Concept Connections: Links to ligand types, oxidation states, and coordination number, which are all essential for understanding bonding and properties of complexes.

Questions

Q 1. Which one is the most likely structure of \(\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) if 1/ 3 of total chlorine of the compound is precipitated by adding \(\mathrm{AgNO}_{3}\);

(a) \(\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}\);

(b) \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3} \mathrm{Cl}_{3}\right] \cdot\left(\mathrm{H}_{2} \mathrm{O}\right)_{3}\);

(c) \(\left[\mathrm{CrCl}_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right] \mathrm{Cl} \cdot 2 \mathrm{H}_{2} \mathrm{O}\);

(d) \(\left[\mathrm{CrCl}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\right] \mathrm{Cl}_{2} \cdot \mathrm{H}_{2} \mathrm{O}\);

Oxidation state determination in complexes


Oxidation State Determination in Complexes

1. Definition and Core Explanation

The oxidation state of the central metal ion in a coordination complex is a numerical representation of its charge after accounting for the charges of all ligands and counter ions in the complex. Determining the oxidation state is crucial for understanding the reactivity, stability, and electronic properties of the coordination compound.

 

- Oxidation State: Represents the total charge on the metal ion when bonded to ligands. It is crucial in predicting the reactivity of the metal, the geometry of the complex, and its stability.

 

For example, in [Fe(CN)\(_6\)]\(^{4-}\), the oxidation state of Fe can be determined by considering the charges of the ligands and the overall charge of the complex.

2. Steps for Determining Oxidation State in Complexes

 

1. Identify Ligand Charges:

   - Anionic Ligands: Ligands like chloride (Cl\(^-\)), cyanide (CN\(^-\)), hydroxide (OH\(^-\)), etc., have negative charges.

   - Neutral Ligands: Ligands such as ammonia (NH\(_3\)), water (H\(_2\)O), carbon monoxide (CO) have no charge.

   - Cationic Ligands: These are rare but could include ligands like NO\(^+\).

 

2. Calculate the Total Charge from Ligands:

   - Multiply the charge of each ligand by the number of such ligands attached to the metal center.

   - Sum the charges of all ligands.

 

3. Consider the Overall Charge of the Complex:

   - The overall charge of the coordination complex is provided in the formula. This could be neutral, positive, or negative.

   - Use this information to set up an equation involving the oxidation state of the metal ion.

 

4. Solve for the Oxidation State of the Metal Ion:

   - Let the oxidation state of the metal be \( x \).

   - Set up the equation considering the charge contributions from ligands and the overall charge.

   - Solve for \( x \).

 

Example:

- In [Co(NH\(_3\))\(_6\)]Cl\(_3\):

  - Ligand: NH\(_3\) is neutral, so it contributes no charge.

  - Counter ions: Cl\(^-\) contributes -3 (since there are three Cl\(^-\) ions).

  - Let the oxidation state of Co be \( x \).

  - \( x + 0 = +3 \) ⟹ \( x = +3 \).

  - Oxidation State of Co: +3.

3. Key Terms and Concepts

- Oxidation State: The effective charge on the metal ion in the complex after accounting for all ligands and counter ions.

- Ligand Charges: Each ligand contributes either a negative, positive, or neutral charge to the metal center.

- Complex Charge: The net charge on the entire coordination complex, which is used to determine the oxidation state.

4. Important Rules, Theorems, and Principles

- Charge Balance Principle: The sum of the charges on the metal ion and ligands must equal the overall charge on the complex.

- Common Ligand Charges:

  - Anionic: Cl\(^-\) (-1), CN\(^-\) (-1), OH\(^-\) (-1).

  - Neutral: NH\(_3\) (0), H\(_2\)O (0), CO (0).

5. Illustrative Diagrams and Visuals

 

1. Oxidation State Calculation Example:

   - Diagram illustrating the coordination sphere of [Cr(H\(_2\)O)\(_4\)Cl\(_2\)]\(^+\), showing ligand charges and how they balance with the metal’s oxidation state.

 

2. Charge Distribution in a Coordination Complex:

   - Flowchart or step-by-step diagram showing how to determine the oxidation state for [Fe(CN)\(_6\)]\(^{3-}\).

 

[Include visuals that show the steps for determining oxidation state, including labeling ligand charges and solving for metal charge.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Determine the oxidation state of the metal ion in [PtCl\(_6\)]\(^{2-}\).

 

- Solution:

  1. Identify Ligands: Six chloride ions (Cl\(^-\)).

  2. Calculate Ligand Charge: Each chloride ion has a charge of -1, so the total ligand charge is \( 6 \times (-1) = -6 \).

  3. Set Up Equation: Let the oxidation state of Pt be \( x \).

     - \( x + (-6) = -2 \)

  4. Solve for \( x \): \( x = +4 \).

  - Answer: The oxidation state of Pt in [PtCl\(_6\)]\(^{2-}\) is +4.

 

Example Problem 2: Calculate the oxidation state of cobalt in [Co(en)\(_2\)Cl\(_2\)]\(^+\), where en (ethylenediamine) is a neutral bidentate ligand.

 

- Solution:

  1. Identify Ligands: Two ethylenediamine (en) ligands and two chloride ions (Cl\(^-\)).

  2. Calculate Ligand Charges:

     - en is neutral, so its contribution is 0.

     - Cl\(^-\) contributes \( 2 \times (-1) = -2 \).

  3. Set Up Equation: Let the oxidation state of Co be \( x \).

     - \( x + 0 + (-2) = +1 \)

  4. Solve for \( x \): \( x = +3 \).

  - Answer: The oxidation state of Co in [Co(en)\(_2\)Cl\(_2\)]\(^+\) is +3.

7. Common Tricks, Shortcuts, and Solving Techniques

- Charge Cancellation: For neutral complexes, the sum of metal and ligand charges must be zero.

- Ligand Type Identification: Quickly identify ligand charges as either negative, neutral, or (rarely) positive to simplify calculations.

8. Patterns in JEE Questions

JEE Advanced questions on oxidation state determination in complexes may involve:

- Determining the oxidation state of a metal in complex ions.

- Using oxidation states to predict the reactivity of the complex.

- Applying the charge balance to multi-ligand complexes.

9. Tips to Avoid Common Mistakes

- Missing Ligand Charges: Always account for every ligand’s charge, particularly in polydentate ligands.

- Incorrect Sign for Charges: Ensure that negative and positive charges are assigned correctly when balancing the equation for oxidation state.

10. Key Points to Remember for Revision

- Oxidation State Calculation: Sum of metal ion and ligand charges must equal the overall charge of the complex.

- Ligand Charges: Know the typical charges of common ligands (e.g., Cl\(^-\) is -1, NH\(_3\) is 0).

- Polydentate Ligands: Some ligands bind through multiple donor atoms but do not contribute extra charges.

11. Real-World Applications and Cross-Chapter Links

- Catalysis: Understanding the oxidation state of metals helps in designing catalysts used in industrial processes.

- Redox Chemistry: Oxidation states are crucial in determining redox behavior of complexes in reactions.

- Cross-Concept Connections: Links to ligand field theory, redox potentials, and coordination numbers in coordination chemistry.

Questions

Q 1. \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) is \(\mathrm{a}\) :;

(a) double salt;

(b) complex compound;

(c) acid;

(d) base;

Isomerism in coordination compounds


Isomerism in Coordination Compounds

1. Definition and Core Explanation

Isomerism in coordination compounds refers to the existence of two or more compounds that have the same molecular formula but different arrangements of atoms or groups in space. This phenomenon is crucial in coordination chemistry because the arrangement of ligands and the spatial orientation of the complex can significantly affect the chemical properties, reactivity, and biological activities of the compound.

 

Isomerism in coordination compounds is broadly classified into structural isomerism and stereoisomerism.

 

- Structural Isomerism: Involves different connectivity of atoms or groups within the coordination compound. Types include ionization isomerism, coordination isomerism, linkage isomerism, and hydrate isomerism.

- Stereoisomerism: Involves different spatial arrangements of ligands around the central metal ion, but with the same connectivity. Types include geometrical isomerism and optical isomerism.

2. Types of Isomerism in Coordination Compounds

 

1. Structural Isomerism:

   - Ionization Isomerism:

     - Occurs when different counter ions are exchanged within the coordination sphere.

     - Example: [Co(NH\(_3\))\(_5\)Br]SO\(_4\) and [Co(NH\(_3\))\(_5\)SO\(_4\)]Br. These compounds give different ions in solution—one gives Br\(^-\) and the other SO\(_4^{2-}\) when dissolved.

   - Coordination Isomerism:

     - Occurs in complexes with both cationic and anionic coordination entities, where ligands are exchanged between the two entities.

     - Example: [Co(NH\(_3\))\(_6\)][Cr(CN)\(_6\)] and [Cr(NH\(_3\))\(_6\)][Co(CN)\(_6\)].

   - Linkage Isomerism:

     - Arises when an ambidentate ligand (a ligand that can bind through different atoms) bonds through different donor atoms.

     - Example: [Co(NO\(_2\))\(_6\)]\(^{3-}\) can exist as nitro (bonded through nitrogen, NO\(_2\)-N) or nitrito (bonded through oxygen, ONO\(_2\)-O) isomers.

   - Hydrate (Solvate) Isomerism:

     - Arises due to the presence of water molecules either inside or outside the coordination sphere.

     - Example: [Cr(H\(_2\)O)\(_6\)]Cl\(_3\) versus [Cr(H\(_2\)O)\(_5\)Cl]Cl\(_2\) \cdot H\(_2\)O.

 

2. Stereoisomerism:

   - Geometrical Isomerism:

     - Occurs in complexes with ligands arranged differently in space, leading to cis (adjacent) or trans (opposite) forms.

     - Example: In [Pt(NH\(_3\))\(_2\)Cl\(_2\)], the cis form has two chloride ions adjacent, while the trans form has them opposite each other.

   - Optical Isomerism:

     - Occurs in complexes that are non-superimposable mirror images of each other (like left and right hands), known as enantiomers.

     - Example: [Cr(en)\(_3\)]\(^{3+}\), where en (ethylenediamine) is a bidentate ligand, forms optically active isomers.

3. Key Terms and Concepts

- Ionization Isomerism: Isomers that yield different ions in solution.

- Linkage Isomerism: Isomers formed by ambidentate ligands bonding through different atoms.

- Geometrical Isomerism: Isomers with different spatial arrangements of ligands (cis/trans).

- Optical Isomerism: Isomers that are non-superimposable mirror images (enantiomers).

4. Important Rules, Theorems, and Principles

- Ambidentate Ligands: Ligands capable of coordinating through different atoms lead to linkage isomerism.

- Cis/Trans Rule: Geometrical isomerism arises when ligands can be positioned adjacent (cis) or opposite (trans) to each other.

- Chirality in Complexes: Optical isomerism occurs if a complex lacks a plane of symmetry and has a chiral structure.

5. Illustrative Diagrams and Visuals

 

1. Geometrical Isomers of [Pt(NH\(_3\))\(_2\)Cl\(_2\)]:

   - Diagram illustrating the cis and trans forms, showing the spatial arrangement of ligands.

 

2. Optical Isomers of [Cr(en)\(_3\)]\(^{3+}\):

   - Diagrams showing non-superimposable mirror images of the complex.

 

3. Linkage Isomerism Example:

   - Diagram showing [Co(NO\(_2\))\(_6\)]\(^{3-}\), highlighting bonding through nitrogen (nitro) and oxygen (nitrito).

 

[Include visuals of isomers, such as cis/trans configurations and mirror images of optical isomers, for better comprehension.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Identify the type of isomerism in [Co(NH\(_3\))\(_5\)Br]SO\(_4\) and [Co(NH\(_3\))\(_5\)SO\(_4\)]Br.

 

- Solution:

  1. Identify Ligands and Counter Ions: Both compounds have the same ligands and counter ions, but their positions differ.

  2. Determine the Isomerism Type: Since the exchange occurs between the counter ion and the ligand, this is ionization isomerism.

  - Answer: The compounds exhibit ionization isomerism.

 

Example Problem 2: Draw the cis and trans isomers of [Pt(NH\(_3\))\(_2\)Cl\(_2\)] and explain their difference.

 

- Solution:

  1. Draw the Structures:

     - Cis Isomer: Both NH\(_3\) ligands are adjacent, and both Cl ligands are adjacent.

     - Trans Isomer: The NH\(_3\) ligands and Cl ligands are opposite each other.

  2. Explain the Difference:

     - In the cis form, similar ligands are adjacent, whereas, in the trans form, similar ligands are on opposite sides.

  - Answer: The cis isomer has adjacent ligands, while the trans isomer has opposite ligands.

7. Common Tricks, Shortcuts, and Solving Techniques

- Cis/Trans Shortcut: For complexes with coordination number 4 or 6, visualize ligands to quickly identify cis or trans configurations.

- Mirror Image Check for Chirality: If a complex has no plane of symmetry, it is likely optically active.

8. Patterns in JEE Questions

JEE Advanced questions on isomerism in coordination compounds may involve:

- Identifying the type of isomerism exhibited by given coordination complexes.

- Drawing geometrical and optical isomers.

- Distinguishing between ionization and linkage isomerism based on ligand changes.

9. Tips to Avoid Common Mistakes

- Confusing Geometrical and Optical Isomerism: Geometrical isomerism deals with the position of ligands, while optical isomerism is about non-superimposable mirror images.

- Missing Ambidentate Ligand Options: Always check if a ligand can bind through multiple atoms, which can lead to linkage isomerism.

10. Key Points to Remember for Revision

- Structural vs. Stereoisomerism: Structural isomerism involves different connectivity, while stereoisomerism involves different spatial arrangements.

- Types of Isomerism: Include ionization, coordination, linkage, hydrate for structural, and geometrical and optical for stereoisomerism.

- Chirality in Complexes: Optical isomers are non-superimposable mirror images, common in octahedral complexes with bidentate ligands.

11. Real-World Applications and Cross-Chapter Links

- Pharmaceutical Chemistry: Optical isomerism is crucial in drug efficacy, as different enantiomers can have different biological effects.

- Catalysis: Geometrical isomers may have different catalytic properties based on the arrangement of active sites.

- Cross-Concept Connections: Links to ligand field theory and coordination number, which affect the possibility of different isomers forming.

Questions

Q 1. The number of ions formed on dissolving one molecule of \(\mathrm{FeSO}_{4}\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) in water is:;

(a) 4;

(b) 5;

(c) 3;

(d) 6;

Geometrical isomerism in complexes


Geometrical Isomerism in Complexes

1. Definition and Core Explanation

Geometrical isomerism is a type of stereoisomerism that occurs in coordination compounds when ligands can be arranged differently around the central metal ion, giving rise to different spatial orientations. This type of isomerism arises when ligands occupy different positions in space around the central metal atom, leading to cis (adjacent) and trans (opposite) forms.

 

Geometrical isomerism is most common in coordination compounds with coordination number 4 or 6:

- In square planar complexes (coordination number 4).

- In octahedral complexes (coordination number 6).

 

It is important to note that geometrical isomerism is possible only if the ligands can be arranged in different spatial orientations relative to each other.

2. Geometrical Isomerism in Different Coordination Geometries

 

1. Square Planar Complexes (Coordination Number 4):

   - Geometrical isomerism is observed when there are at least two different types of ligands.

   - Cis Form: Similar ligands are positioned adjacent to each other.

   - Trans Form: Similar ligands are positioned opposite to each other.

   - Example: [Pt(NH\(_3\))\(_2\)Cl\(_2\)]:

     - In the cis isomer, both chloride ligands are adjacent, while in the trans isomer, they are opposite each other.

 

2. Octahedral Complexes (Coordination Number 6):

   - Geometrical isomerism occurs when there are different types of ligands arranged in the octahedral geometry.

   - Cis Form: Identical ligands are next to each other.

   - Trans Form: Identical ligands are positioned at 180° from each other.

   - Example: [Co(NH\(_3\))\(_4\)Cl\(_2\)]:

     - In the cis form, the two chloride ions are adjacent, while in the trans form, they are positioned opposite to each other.

 

Geometrical isomerism is not possible in tetrahedral complexes since all the positions are equivalent, which makes distinguishing between different spatial arrangements impossible.

3. Key Terms and Concepts

- Cis Isomer: Ligands of the same type are positioned next to each other.

- Trans Isomer: Ligands of the same type are positioned opposite each other.

- Square Planar and Octahedral Geometry: Geometrical isomerism is observed in these geometries due to the distinct spatial positions available for ligands.

4. Important Rules, Theorems, and Principles

- Square Planar Isomerism: Observed in complexes with coordination number 4, usually with metals like Pt(II) or Ni(II).

- Octahedral Isomerism: Observed in complexes with coordination number 6, where different types of ligands can occupy adjacent or opposite positions.

- Cis-Trans Notation: Cis indicates that identical ligands are adjacent, while trans indicates that they are opposite.

5. Illustrative Diagrams and Visuals

 

1. Cis and Trans Isomers of [Pt(NH\(_3\))\(_2\)Cl\(_2\)]:

   - Diagram showing the square planar geometry with cis and trans arrangements of NH\(_3\) and Cl ligands.

 

2. Cis and Trans Isomers of [Co(NH\(_3\))\(_4\)Cl\(_2\)]:

   - Diagram illustrating the octahedral geometry with the cis and trans positioning of the chloride ions.

 

3. Comparison of Ligand Positions in Different Geometries:

   - Visual showing the distinction between square planar and octahedral geometries and how geometrical isomerism arises in each.

 

[Include visuals to illustrate cis/trans isomers in both square planar and octahedral complexes.]

 6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Identify the cis and trans isomers of [Pt(NH\(_3\))\(_2\)Cl\(_2\)] and explain the difference in their properties.

 

- Solution:

  1. Draw the Isomers:

     - Cis Isomer: Both NH\(_3\) molecules are adjacent, and both Cl atoms are adjacent.

     - Trans Isomer: The NH\(_3\) molecules are opposite each other, and the Cl atoms are also opposite.

  2. Explain the Difference:

     - The cis form often has different physical properties, such as solubility, compared to the trans form. The cis isomer may also exhibit different chemical reactivity, especially in substitution reactions.

  - Answer: Cis isomer has adjacent ligands, while trans has opposite ligands. The physical and chemical properties differ between these forms.

 

Example Problem 2: Draw and identify the cis and trans isomers of [Co(NH\(_3\))\(_4\)Cl\(_2\)].

 

- Solution:

  1. Draw the Octahedral Geometry:

     - In the cis isomer, both Cl ligands are adjacent, while in the trans isomer, they are positioned opposite each other.

  2. Identification:

     - Cis Isomer: Cl ligands are next to each other.

     - Trans Isomer: Cl ligands are opposite.

  - Answer: The cis form has chloride ions adjacent, whereas the trans form has them opposite.

7. Common Tricks, Shortcuts, and Solving Techniques

- Identify Ligand Positions: For square planar and octahedral complexes, visualize the positions of identical ligands to quickly determine cis or trans forms.

- Use Models: Drawing or using molecular models can help visualize the difference between cis and trans isomers, especially in octahedral geometry.

 

---

 

 8. Patterns in JEE Questions

JEE Advanced questions on geometrical isomerism may involve:

- Drawing the cis and trans isomers of given coordination complexes.

- Predicting the reactivity or properties of the isomers based on their spatial arrangement.

- Identifying geometrical isomers from given names or formulas.

9. Tips to Avoid Common Mistakes

- Confusing Cis and Trans: Remember that cis means adjacent and trans means opposite; it helps to visualize the geometry.

- Incorrect Geometry Identification: Geometrical isomerism does not occur in tetrahedral complexes; ensure the coordination number and geometry allow for cis/trans forms.

10. Key Points to Remember for Revision

- Cis and Trans in Square Planar: Common in [Pt(NH\(_3\))\(_2\)Cl\(_2\)] type complexes.

- Cis and Trans in Octahedral: Occurs when there are at least two different types of ligands.

- No Geometrical Isomerism in Tetrahedral Complexes: All four positions are equivalent, making it impossible to have distinct cis and trans forms.

11. Real-World Applications and Cross-Chapter Links

- Medicinal Chemistry: The cis form of [PtCl\(_2\)(NH\(_3\))\(_2\)] (cisplatin) is used as an anticancer drug, while the trans form is biologically inactive.

- Catalysis: The activity of coordination catalysts can vary between cis and trans isomers due to the different positioning of active sites.

- Cross-Concept Connections: Links to ligand field theory, hybridization, and coordination geometry, which determine the possible isomers.

Questions

Q 1. The solution of \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) in water will;

(a) give a test \(\mathrm{K}^{+}\);

(b) give a test \(\mathrm{Fe}^{2+}\);

(c) give a test of \(\mathrm{CN}^{-}\);

(d) give a test of \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4}\);

Optical isomerism in coordination complexes


Optical Isomerism in Coordination Complexes

1. Definition and Core Explanation

Optical isomerism in coordination compounds occurs when molecules are non-superimposable mirror images of each other. Such compounds are called optical isomers or enantiomers. They differ from each other in the way they rotate plane-polarized light: one isomer rotates light to the right (dextrorotatory, +) while the other rotates it to the left (levorotatory, -).

 

Optical isomerism arises primarily in octahedral complexes with certain types of ligands, especially when there is no plane of symmetry, making the complex chiral. Optical isomerism is less common in tetrahedral and square planar complexes due to the requirement of asymmetry.

 

A key characteristic of optical isomers is that they have identical chemical and physical properties, except for their behavior towards plane-polarized light and their interactions with other chiral substances.

2. Conditions for Optical Isomerism in Coordination Complexes

 

1. Lack of Symmetry:

   - Optical isomerism occurs in complexes that lack a plane of symmetry, a center of symmetry, or a rotational axis of symmetry.

   - The complex must be chiral, meaning its mirror image cannot be superimposed on the original complex.

 

2. Octahedral Complexes:

   - Optical isomerism is commonly observed in octahedral complexes with bidentate ligands (e.g., ethylenediamine (en)).

   - For example, [Co(en)\(_3\)]\(^{3+}\) is an octahedral complex that shows optical isomerism due to the arrangement of the three bidentate ligands.

 

3. Tetrahedral Complexes:

   - Optical isomerism is possible if all four ligands attached to the metal are different (similar to the situation in a carbon atom with four different substituents, leading to chirality).

 3. Key Terms and Concepts

- Optical Isomers (Enantiomers): Non-superimposable mirror images of each other.

- Chirality: A property of a molecule that makes it non-superimposable on its mirror image, leading to the existence of enantiomers.

- Dextrorotatory (+): An isomer that rotates plane-polarized light to the right.

- Levorotatory (-): An isomer that rotates plane-polarized light to the left.

4. Important Rules, Theorems, and Principles

- Chirality Requirement: Optical isomerism only occurs if the complex is chiral, meaning it lacks symmetry elements that would make the mirror image superimposable.

- Enantiomer Properties: Enantiomers have identical chemical properties, except for their effect on plane-polarized light and their interactions with other chiral molecules.

5. Illustrative Diagrams and Visuals

 

1. Optical Isomers of [Co(en)\(_3\)]\(^{3+}\):

   - Diagram illustrating the non-superimposable mirror images of [Co(en)\(_3\)]\(^{3+}\).

   - Each enantiomer is shown to be a mirror image of the other, demonstrating how they cannot be superimposed.

 

2. Tetrahedral Complex Showing Chirality:

   - Diagram of a tetrahedral complex with four different ligands, showing the mirror images that are non-superimposable.

 

3. Plane-Polarized Light Rotation:

   - Diagram showing how the two optical isomers rotate plane-polarized light in opposite directions.

 

[Include diagrams to visually demonstrate the concept of chirality and the non-superimposable nature of optical isomers.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Determine if [Co(en)\(_3\)]\(^{3+}\) can exhibit optical isomerism.

 

- Solution:

  1. Identify Ligands and Geometry: The complex contains three en (ethylenediamine) ligands, and the geometry is octahedral.

  2. Check for Symmetry: The three en ligands create an asymmetrical arrangement, which means the complex is chiral and lacks a plane of symmetry.

  3. Conclusion: [Co(en)\(_3\)]\(^{3+}\) can exhibit optical isomerism.

  - Answer: [Co(en)\(_3\)]\(^{3+}\) exhibits optical isomerism.

 

Example Problem 2: Explain why [PtCl\(_2\)(en)] cannot show optical isomerism.

 

- Solution:

  1. Identify Geometry: The complex has a square planar geometry with two Cl ligands and one en ligand.

  2. Check for Symmetry: The presence of a plane of symmetry through the metal and ligands means that the complex is achiral.

  - Answer: [PtCl\(_2\)(en)] cannot show optical isomerism because it has a plane of symmetry.

7. Common Tricks, Shortcuts, and Solving Techniques

- Look for Bidentate Ligands: If the complex contains bidentate ligands such as en, it is more likely to be chiral and show optical isomerism.

- Symmetry Check: Always check for symmetry elements (plane, center, axis). A lack of these elements typically indicates chirality.

8. Patterns in JEE Questions

JEE Advanced questions on optical isomerism in coordination complexes may involve:

- Identifying which complexes are capable of showing optical isomerism.

- Drawing the mirror images of given complexes.

- Distinguishing between chiral and achiral complexes based on ligand arrangement.

9. Tips to Avoid Common Mistakes

- Confusing Geometrical and Optical Isomerism: Remember that geometrical isomerism deals with the positioning of ligands (cis/trans), while optical isomerism deals with mirror images that are non-superimposable.

- Symmetry Analysis: Failing to analyze symmetry can lead to incorrect conclusions about the presence of optical isomerism.

 10. Key Points to Remember for Revision

- Optical Isomers Are Non-Superimposable: The two mirror images (enantiomers) cannot be placed on top of each other and look identical.

- Chirality: A chiral complex lacks symmetry, making optical isomerism possible.

- Bidentate Ligands in Octahedral Complexes: Often lead to optical isomerism due to their ability to create asymmetry in the complex.

11. Real-World Applications and Cross-Chapter Links

- Pharmaceutical Chemistry: Optical isomerism is crucial in drug development because different enantiomers of a drug can have vastly different effects.

- Catalysis: The activity of a coordination complex catalyst can vary depending on its chirality, making optical isomers important in enantioselective catalysis.

- Cross-Concept Connections: Links to chirality, symmetry, and stereochemistry in organic chemistry are essential for understanding optical isomerism.

Questions

Q 1. In the coordination compound, \(\mathrm{K}_{4}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]\), the oxidation state of nickel is;

(a) 0;

(b) +1;

(c) +2;

(d) -1;

Crystal field theory and splitting of d-orbitals


Crystal Field Theory and Splitting of d-Orbitals

1. Definition and Core Explanation

Crystal Field Theory (CFT) is a model used to describe the interaction between a central metal ion and its surrounding ligands in a coordination complex. This theory helps explain the electronic structure, color, magnetic properties, and stability of coordination complexes by focusing on the electrostatic interactions between the metal ion and the ligands.

 

- Crystal Field Splitting: When ligands approach the central metal ion, their negative charges interact with the d-orbitals of the metal ion, leading to an uneven distribution of energy among the d-orbitals. This results in a splitting of the d-orbitals into two sets of different energy levels.

- Octahedral and Tetrahedral Fields: The splitting pattern of the d-orbitals depends on the geometry of the complex, which can be octahedral, tetrahedral, or square planar.

 

CFT treats ligands as point charges that create an electrostatic field, which influences the energy of the d-orbitals of the metal ion. This interaction leads to the phenomenon known as crystal field splitting.

2. Splitting of d-Orbitals in Different Geometries

 

1. Octahedral Field:

   - In an octahedral field, six ligands approach the metal ion along the x, y, and z axes.

   - The d-orbitals split into two sets:

     - \(e_g\) Set (Higher Energy): \(d_{z^2}\), \(d_{x^2-y^2}\).

     - \(t_{2g}\) Set (Lower Energy): \(d_{xy}\), \(d_{xz}\), \(d_{yz}\).

   - The energy difference between the two sets is called the crystal field splitting energy (\(\Delta_o\)).

   - The electrons occupy these orbitals following the Hund's rule and Aufbau principle.

 

2. Tetrahedral Field:

   - In a tetrahedral field, four ligands approach the metal ion between the axes.

   - The d-orbitals split into two sets, but in reverse order compared to the octahedral field:

     - \(t_2\) Set (Higher Energy): \(d_{xy}\), \(d_{xz}\), \(d_{yz}\).

     - \(e\) Set (Lower Energy): \(d_{z^2}\), \(d_{x^2-y^2}\).

   - The splitting energy in tetrahedral complexes (\(\Delta_t\)) is smaller than that in octahedral complexes.

 

3. Square Planar Field:

   - In a square planar field, ligands approach only in the xy-plane, leading to a distinct splitting pattern.

   - The \(d_{x^2-y^2}\) orbital is highest in energy because it lies directly along the axes where ligands are positioned.

3. Key Terms and Concepts

- Crystal Field Splitting Energy (\(\Delta\)): The energy difference between the sets of d-orbitals after splitting.

- Octahedral Splitting (\(\Delta_o\)): Splitting pattern in octahedral complexes where \(t_{2g}\) is lower in energy than \(e_g\).

- Tetrahedral Splitting (\(\Delta_t\)): Splitting pattern in tetrahedral complexes where \(e\) is lower in energy than \(t_2\).

- Spectrochemical Series: A list of ligands arranged in order of their ability to cause d-orbital splitting, ranging from weak field to strong field ligands.

4. Important Rules, Theorems, and Principles

- Hund’s Rule: Electrons will occupy orbitals singly as far as possible before pairing.

- Aufbau Principle: Electrons fill the lowest available energy levels first.

- Spectrochemical Series: Ligands like I\(^-\) and Br\(^-\) are weak field ligands (cause small splitting), while CN\(^-\) and CO are strong field ligands (cause large splitting).

5. Illustrative Diagrams and Visuals

 

1. Octahedral Splitting Diagram:

   - Diagram showing the splitting of the five degenerate d-orbitals into the \(e_g\) and \(t_{2g}\) sets, with \(\Delta_o\) marked.

 

2. Tetrahedral Splitting Diagram:

   - Diagram illustrating the reverse splitting of d-orbitals in a tetrahedral field, with \(t_2\) being higher in energy.

 

3. Square Planar Splitting Diagram:

   - Diagram showing the splitting of d-orbitals in a square planar field, emphasizing the high energy of the \(d_{x^2-y^2}\) orbital.

 

[Include visuals to show the splitting patterns in different geometries to aid understanding.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Explain the crystal field splitting of d-orbitals in an octahedral complex and predict the distribution of electrons in [Fe(CN)\(_6\)]\(^{4-}\) (Fe is in the +2 oxidation state).

 

- Solution:

  1. Oxidation State of Fe: In [Fe(CN)\(_6\)]\(^{4-}\), the oxidation state of Fe is +2, so the electronic configuration is 3d\(^6\).

  2. Identify Ligand Field: CN\(^-\) is a strong field ligand, which leads to a large \(\Delta_o\), favoring pairing of electrons in the lower energy \(t_{2g}\) orbitals.

  3. Electron Distribution:

     - Six electrons will occupy the lower energy \(t_{2g}\) set, leading to a low-spin configuration.

  - Answer: All six electrons occupy the \(t_{2g}\) set, making the complex low spin.

 

Example Problem 2: Describe the difference in crystal field splitting between octahedral and tetrahedral complexes.

 

- Solution:

  1. Octahedral Splitting: In octahedral complexes, ligands approach along the axes, splitting the d-orbitals into \(t_{2g}\) (lower) and \(e_g\) (higher) sets.

  2. Tetrahedral Splitting: In tetrahedral complexes, ligands approach between the axes, resulting in \(t_2\) (higher) and \(e\) (lower) sets, with the splitting energy \(\Delta_t\) being much smaller.

  - Answer: In octahedral complexes, \(t_{2g}\) is lower in energy, while in tetrahedral complexes, \(e\) is lower in energy. The magnitude of splitting in tetrahedral complexes (\(\Delta_t\)) is significantly less than that in octahedral complexes (\(\Delta_o\)).

 7. Common Tricks, Shortcuts, and Solving Techniques

- High vs. Low Spin: Use the spectrochemical series to determine whether a ligand is strong or weak field, which helps predict high-spin or low-spin configurations.

- Splitting Energy Relationship: Remember that \(\Delta_t\) is approximately 4/9 of \(\Delta_o\), which helps in comparing the energy differences between octahedral and tetrahedral fields.

8. Patterns in JEE Questions

JEE Advanced questions on crystal field theory may involve:

- Drawing the crystal field splitting diagrams for different geometries.

- Predicting the number of unpaired electrons in a given complex.

- Comparing the magnetic properties of high-spin and low-spin complexes.

9. Tips to Avoid Common Mistakes

- Confusing \(t_{2g}\) and \(e_g\): In octahedral complexes, \(t_{2g}\) is lower in energy, while in tetrahedral complexes, \(t_2\) is higher.

- Misinterpreting the Spectrochemical Series: Always refer to the spectrochemical series to determine whether a ligand will cause significant splitting.

10. Key Points to Remember for Revision

- Octahedral Splitting: \(t_{2g}\) is lower in energy, \(e_g\) is higher.

- Tetrahedral Splitting: \(t_2\) is higher in energy, \(e\) is lower.

- Spectrochemical Series: Helps determine whether the complex is high spin or low spin.

- Electron Configuration: Follow Hund’s rule and the Aufbau principle when filling the split d-orbitals.

11. Real-World Applications and Cross-Chapter Links

- Color of Complexes: The color observed in coordination compounds arises from the d-d transitions between split d-orbitals.

- Magnetism: The number of unpaired electrons, influenced by the crystal field splitting, determines whether a complex is paramagnetic or diamagnetic.

- Cross-Concept Connections: Links to ligand field theory, magnetic properties, and electronic transitions are crucial for understanding the impact of d-orbital splitting.

Questions

Q 1. The coordination number of a central metal atom in a complex is determined by;

(a) the number of ligands around a metal ion bonded by sigma and pi-bonds both;

(b) the number of ligands around a metal ion bonded by pi-bonds;

(c) the number of ligands around a metal ion bonded by sigma bonds;

(d) the number of only anionic ligands bonded to the metal ion.;

Ligand field strength and spectrochemical series


Ligand Field Strength and Spectrochemical Series

1. Definition and Core Explanation

The ligand field strength refers to the ability of a ligand to cause splitting of the d-orbitals in a coordination complex, which is a central concept in Crystal Field Theory (CFT). Ligands differ in their capability to induce crystal field splitting, which ultimately affects the electronic configuration, color, magnetic properties, and stability of the coordination complex.

 

The spectrochemical series is an experimentally determined sequence of ligands arranged in increasing order of their ability to cause d-orbital splitting. The strength of the ligand field affects whether the complex will be high spin or low spin, which in turn impacts the complex’s magnetic properties.

 

- Weak Field Ligands: Cause smaller d-orbital splitting and often result in high-spin complexes.

- Strong Field Ligands: Cause greater d-orbital splitting and can result in low-spin complexes if pairing of electrons is energetically favorable.

2. The Spectrochemical Series

 

The spectrochemical series lists ligands in order of their field strength, from weak field (causing minimal splitting) to strong field (causing maximum splitting). The series is as follows:

 

I\(^-\) < Br\(^-\) < S\(^2-\) < SCN\(^-\) < Cl\(^-\) < F\(^-\) < OH\(^-\) < C\(_2\)O\(_4\)^{2-} < H\(_2\)O < NCS\(^-\) < NH\(_3\) < en (ethylenediamine) < bpy (2,2'-bipyridine) < phen (1,10-phenanthroline) < NO\(_2^-\) < PPh\(_3\) < CN\(^-\) < CO

 

1. Weak Field Ligands:

   - Examples: I\(^-\), Br\(^-\), Cl\(^-\).

   - These ligands cause small crystal field splitting energy (\(\Delta\)), leading to high-spin complexes.

   - In octahedral complexes, electrons occupy both the lower and higher energy d-orbitals singly before pairing, following Hund’s rule.

 

2. Intermediate Field Ligands:

   - Examples: H\(_2\)O, NH\(_3\).

   - These ligands lie in the middle of the spectrochemical series and their effect on splitting depends on the metal ion and other conditions.

 

3. Strong Field Ligands:

   - Examples: CN\(^-\), CO, NO\(_2^-\).

   - These ligands cause large crystal field splitting energy (\(\Delta\)), leading to low-spin complexes.

   - In octahedral complexes, the electrons tend to pair in the lower energy \(t_{2g}\) set before occupying the higher \(e_g\) orbitals.

 

The strength of the ligand field is crucial in determining several properties of the coordination complex, including its magnetism, color, and reactivity.

3. Key Terms and Concepts

- Ligand Field Strength: The ability of a ligand to cause splitting of the metal ion’s d-orbitals.

- Spectrochemical Series: An experimentally derived list of ligands ordered by their field strength.

- High Spin vs. Low Spin: Refers to the arrangement of electrons in d-orbitals, depending on the crystal field splitting energy relative to the pairing energy.

4. Important Rules, Theorems, and Principles

- Crystal Field Splitting Energy (\(\Delta\)): The energy difference between split d-orbitals, influenced by ligand field strength.

- Hund's Rule: Electrons will occupy orbitals singly before pairing up, which is relevant when determining high spin versus low spin configurations.

- Pairing Energy: The energy required to pair electrons in an orbital; determines whether a complex will be high spin or low spin in the presence of a particular ligand.

5. Illustrative Diagrams and Visuals

 

1. Spectrochemical Series Diagram:

   - Diagram showing the spectrochemical series in increasing order of ligand field strength, from weak field to strong field.

 

2. High Spin vs. Low Spin in Octahedral Complexes:

   - Diagram illustrating the difference in electron arrangement for high-spin and low-spin complexes in an octahedral field.

 

3. Crystal Field Splitting for Weak and Strong Field Ligands:

   - Diagram comparing the splitting pattern and electron distribution in a metal complex with a weak field ligand versus a strong field ligand.

 

[Include visuals to illustrate the concept of the spectrochemical series and the impact of weak vs. strong field ligands on electron configuration.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Determine if [Fe(CN)\(_6\)]\(^{4-}\) is a high-spin or low-spin complex. (Fe is in the +2 oxidation state)

 

- Solution:

  1. Oxidation State of Fe: In [Fe(CN)\(_6\)]\(^{4-}\), the oxidation state of Fe is +2, so the electronic configuration is 3d\(^6\).

  2. Identify Ligand Field Strength: CN\(^-\) is a strong field ligand, which causes large splitting energy (\(\Delta_o\)).

  3. Electron Configuration:

     - Since \(\Delta_o\) is large, the electrons will pair in the lower energy \(t_{2g}\) orbitals before occupying the higher energy \(e_g\) orbitals, resulting in a low-spin configuration.

  - Answer: [Fe(CN)\(_6\)]\(^{4-}\) is a low-spin complex.

 

Example Problem 2: Determine the number of unpaired electrons in [CoF\(_6\)]\(^{3-}\). (Co is in the +3 oxidation state)

 

- Solution:

  1. Oxidation State of Co: In [CoF\(_6\)]\(^{3-}\), the oxidation state of Co is +3, so the electronic configuration is 3d\(^6\).

  2. Identify Ligand Field Strength: F\(^-\) is a weak field ligand, which causes small splitting energy (\(\Delta_o\)).

  3. Electron Configuration:

     - With a weak field ligand, the complex will be high-spin, and electrons will occupy all d-orbitals singly before pairing.

     - There are 4 unpaired electrons in the \(t_{2g}\) and \(e_g\) orbitals.

  - Answer: [CoF\(_6\)]\(^{3-}\) has 4 unpaired electrons.

7. Common Tricks, Shortcuts, and Solving Techniques

- Spectrochemical Series Reference: Memorize common ligands and their positions in the spectrochemical series to quickly determine if a ligand is strong or weak field.

- Use of Field Strength to Determine Spin: Strong field ligands often lead to low-spin complexes, while weak field ligands lead to high-spin complexes.

8. Patterns in JEE Questions

JEE Advanced questions on ligand field strength and the spectrochemical series may involve:

- Predicting whether a given complex is high-spin or low-spin based on the ligand.

- Determining the number of unpaired electrons in a complex.

- Understanding the effect of different ligands on magnetic properties.

9. Tips to Avoid Common Mistakes

- Misplacing Ligands in the Spectrochemical Series: Always refer to a reliable source for the correct order of ligands in the spectrochemical series.

- Incorrect Spin State Assignment: Ensure that the splitting energy (\(\Delta\)) is compared to the pairing energy to determine if a complex is high-spin or low-spin.

10. Key Points to Remember for Revision

- Spectrochemical Series: Ligands like CN\(^-\) and CO are strong field ligands; I\(^-\) and Cl\(^-\) are weak field ligands.

- High Spin vs. Low Spin: Depends on the comparison between crystal field splitting energy (\(\Delta\)) and pairing energy.

- Electron Configuration: High-spin complexes have more unpaired electrons, while low-spin complexes have fewer due to electron pairing in lower energy orbitals.

11. Real-World Applications and Cross-Chapter Links

- Magnetic Properties: The number of unpaired electrons determines if a complex is paramagnetic (unpaired electrons) or diamagnetic (no unpaired electrons).

- Color of Complexes: The ligand field strength affects the energy gap (\(\Delta\)), which corresponds to the wavelength of visible light absorbed, giving rise to the color of the complex.

- Cross-Concept Connections: Links to electronic transitions, magnetism, and coordination geometry are crucial for understanding the impact of ligand field strength.

Questions

Q 1. The oxidation state of \(\mathrm{Cr}\) in \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right]^{+}\)is;

(a) 0;

(b) +1;

(c) +2;

(d) +3;

Bonding in metal carbonyls


Bonding in Metal Carbonyls

1. Definition and Core Explanation

Metal carbonyls are coordination compounds formed between a transition metal and carbon monoxide (CO) ligands. In metal carbonyls, CO acts as a ligand that forms a bond with the metal center through a combination of σ-donation and π-backbonding. The unique dual nature of bonding in metal carbonyls makes them an important class of organometallic compounds, often used in catalysis and industrial processes.

 

- σ-Donation: The carbon in the CO ligand donates a lone pair of electrons to the metal atom, forming a σ-bond. This donation occurs from the lone pair on the carbon atom, which is in a sp hybrid orbital, resulting in a strong metal-ligand bond.

- π-Backbonding: The metal, in turn, can donate electron density from its d-orbitals back to the empty π\(^\) anti-bonding orbital of the CO ligand, creating a π-bond. This process is known as π-back donation or π-backbonding and stabilizes the metal-ligand bond.

 

This synergic bonding mechanism, where the σ-donation from CO is complemented by π-back donation from the metal, leads to increased bond strength and stability of the metal carbonyl complex.

2. Nature of Bonding in Metal Carbonyls

 

1. σ-Bonding:

   - σ-donation occurs when the carbon atom of the CO ligand donates a lone pair of electrons to the empty orbital of the metal center.

   - This type of bonding is common in coordination complexes, where ligands act as electron donors.

 

2. π-Backbonding:

   - In π-backbonding, the metal with filled d-orbitals donates electron density back to the empty π\(^\) anti-bonding orbital of CO.

   - This interaction strengthens the metal-ligand bond but weakens the C-O bond, resulting in a lower bond order of the CO molecule compared to free CO.

 

3. Bond Strength and Properties:

   - The presence of π-back donation results in a shorter and stronger metal-carbon bond but weakens the carbon-oxygen bond within the CO ligand.

   - Bond Order of CO in metal carbonyls is reduced compared to free CO due to the partial occupation of the π\(^\) orbital.

 

4. Synergic Effect:

   - The bonding in metal carbonyls is often described as synergic because the metal donates electrons into the π\(^\) orbital of CO, while CO donates electrons to the metal through σ-bonding.

   - This two-way electron donation enhances both the stability of the metal-ligand bond and the overall stability of the complex.

3. Key Terms and Concepts

- σ-Donation: The donation of an electron pair from the CO ligand to the metal, forming a σ-bond.

- π-Backbonding: The donation of electron density from the metal’s d-orbital to the empty π\(^\) orbital of the CO ligand.

- Synergic Bonding: A type of bonding where σ-donation and π-back donation reinforce each other, enhancing stability.

- Bond Order: The number of chemical bonds between a pair of atoms. In metal carbonyls, the bond order of CO is reduced compared to free CO due to π-backbonding.

4. Important Rules, Theorems, and Principles

- Synergic Bonding Mechanism: The simultaneous occurrence of σ-donation from CO to the metal and π-back donation from the metal to CO stabilizes the metal-carbonyl bond.

- Bond Strength: π-backbonding weakens the internal C-O bond of CO while strengthening the metal-carbon bond.

- Infrared Spectroscopy: The extent of π-backbonding can be measured using IR spectroscopy, where a lower C-O stretching frequency indicates stronger backbonding and hence a weaker C-O bond.

5. Illustrative Diagrams and Visuals

 

1. σ-Donation and π-Backbonding Mechanism:

   - Diagram illustrating the lone pair on the carbon of CO donating to the metal, and the metal back donating to the π\(^\) orbital of CO.

 

2. Bonding in Metal Carbonyls:

   - Diagram showing the metal-ligand interaction in [Fe(CO)\(_5\)], with arrows indicating the direction of σ-donation and π-backbonding.

 

3. Molecular Orbitals in Metal Carbonyls:

   - Diagram depicting the molecular orbitals involved in π-backbonding, emphasizing the interaction between metal d-orbitals and the CO π\(^\) orbitals.

 

[Include visuals to demonstrate the dual bonding mechanism in metal carbonyls, with emphasis on the synergy between σ-donation and π-backbonding.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Describe the bonding in [Ni(CO)\(_4\)] using the concept of σ-donation and π-backbonding.

 

- Solution:

  1. Identify Ligand and Metal: CO is the ligand, and Ni is the metal center. Nickel is in the zero oxidation state in [Ni(CO)\(_4\)].

  2. σ-Donation: The carbon atom of each CO ligand donates a lone pair of electrons to the empty orbitals of Ni, forming a σ-bond.

  3. π-Backbonding: The d-electrons of Ni back-donate to the empty π\(^\) orbital of CO, strengthening the metal-carbon bond.

  - Answer: The bonding in [Ni(CO)\(_4\)] is characterized by σ-donation from CO to Ni and π-backbonding from Ni to CO, resulting in a stable complex.

 

Example Problem 2: Explain how IR spectroscopy can be used to determine the extent of π-backbonding in metal carbonyls.

 

- Solution:

  1. C-O Bond Stretching Frequency: The C-O bond stretching frequency in IR spectroscopy indicates the strength of the C-O bond.

  2. Effect of π-Backbonding: π-backbonding weakens the C-O bond, leading to a lower stretching frequency in the IR spectrum compared to free CO.

  - Answer: The extent of π-backbonding can be determined by the C-O stretching frequency; a lower frequency indicates stronger π-backbonding and a weaker C-O bond.

 7. Common Tricks, Shortcuts, and Solving Techniques

- IR Spectroscopy Clues: Use IR spectroscopy to determine the strength of the C-O bond. A lower frequency indicates greater π-backbonding.

- Electron Counting: When evaluating stability, count the number of electrons donated through σ and π interactions. Stable metal carbonyls often obey the 18-electron rule.

 

---

 

 8. Patterns in JEE Questions

JEE Advanced questions on bonding in metal carbonyls may involve:

- Describing the nature of bonding in metal carbonyls, specifically σ-donation and π-backbonding.

- Using IR spectral data to infer the extent of π-backbonding.

- Predicting the electron configuration and stability of a given metal carbonyl complex.

9. Tips to Avoid Common Mistakes

- Misinterpreting Bonding Mechanism: Remember that σ-donation is from CO to metal, while π-backbonding is from metal to CO.

- Overlooking IR Data: When interpreting IR spectroscopy, do not forget that a lower C-O stretching frequency means stronger π-backbonding.

10. Key Points to Remember for Revision

- σ-Donation and π-Backbonding: CO donates electrons to the metal through a σ-bond, and the metal donates electrons back to CO through π-backbonding.

- Synergic Bonding: The combined effect of σ and π interactions stabilizes the metal carbonyl complex.

- IR Spectroscopy: A lower C-O stretching frequency in IR indicates stronger π-backbonding, weakening the internal C-O bond.

11. Real-World Applications and Cross-Chapter Links

- Catalysis: Metal carbonyls like [Fe(CO)\(_5\)] are used as catalysts in organic reactions such as hydroformylation.

- Organometallic Chemistry: Metal carbonyls are a key class of compounds in organometallic chemistry, demonstrating the unique interaction between organic ligands and metal centers.

- Cross-Concept Connections: Links to molecular orbital theory, coordination chemistry, and IR spectroscopy are essential for understanding the bonding in metal carbonyls.

Questions

Q 1. In \(\mathrm{Ni}(\mathrm{CO})_{4}^{-}\), oxidation number of \(\mathrm{Ni}\) is :;

(a) 4;

(b) -4;

(c) 0;

(d) +2;

Magnetic properties of coordination compounds


Magnetic Properties of Coordination Compounds

1. Definition and Core Explanation

The magnetic properties of coordination compounds are determined by the presence of unpaired electrons in the d-orbitals of the central metal ion. The magnetic behavior of a compound can be broadly classified as paramagnetic or diamagnetic, depending on whether it contains unpaired electrons.

 

- Paramagnetism: Compounds that have one or more unpaired electrons are paramagnetic. These compounds are attracted by a magnetic field. The magnetic moment is often expressed in units of Bohr magnetons (\(\mu_B\)).

- Diamagnetism: Compounds with no unpaired electrons are diamagnetic. These compounds are weakly repelled by a magnetic field.

- The magnetic moment can be calculated to provide insight into the number of unpaired electrons and the type of spin configuration in the complex.

 

The magnetic properties depend on the electronic configuration of the metal ion, the ligand field strength, and the geometry of the complex.

2. Factors Affecting Magnetic Properties

 

1. Electronic Configuration:

   - The d-electron count of the metal ion is crucial in determining whether it will have unpaired electrons.

   - For example, Fe\(^2+\) with a 3d\(^6\) configuration can exhibit either a high-spin or low-spin arrangement, depending on the ligands.

 

2. Crystal Field Splitting and Ligand Field Strength:

   - The strength of the ligand field affects the crystal field splitting energy (\(\Delta\)), which influences whether electrons pair up or remain unpaired.

   - Weak field ligands (e.g., F\(^-\), Cl\(^-\)) generally lead to high-spin complexes with more unpaired electrons.

   - Strong field ligands (e.g., CN\(^-\), CO) lead to low-spin complexes, often resulting in fewer unpaired electrons.

 

3. Geometry of the Complex:

   - Octahedral complexes can exhibit either high-spin or low-spin configurations, depending on the ligand field strength.

   - Tetrahedral complexes typically have high-spin configurations due to the smaller splitting energy (\(\Delta_t\)), which is insufficient to force electron pairing.

   - Square Planar complexes, especially with d\(^8\) configurations (e.g., Ni\(^2+\), Pt\(^2+\)), tend to be diamagnetic due to strong ligand fields causing complete pairing of electrons.

3. Key Terms and Concepts

- Paramagnetism: Property of compounds with unpaired electrons that are attracted to magnetic fields.

- Diamagnetism: Property of compounds with all paired electrons, leading to weak repulsion by a magnetic field.

- Magnetic Moment (\(\mu\)): A measure of the strength of a compound's magnetic behavior, often calculated using the formula \(\mu = \sqrt{n(n + 2)}\) Bohr magnetons, where \(n\) is the number of unpaired electrons.

4. Important Rules, Theorems, and Principles

- Crystal Field Splitting and Spin State: The crystal field splitting energy (\(\Delta\)) determines whether the complex will adopt a high-spin or low-spin state, affecting the number of unpaired electrons.

- Hund's Rule: Electrons will occupy degenerate orbitals singly before pairing, which influences the magnetic properties of high-spin complexes.

5. Illustrative Diagrams and Visuals

 

1. High-Spin vs. Low-Spin in Octahedral Complexes:

   - Diagram illustrating the electron distribution in the t\(_{2g}\) and e\(_g\) orbitals for both high-spin and low-spin configurations.

 

2. Magnetic Moments in Coordination Compounds:

   - Diagram showing examples of paramagnetic and diamagnetic complexes, along with their corresponding magnetic moments.

 

3. Crystal Field Splitting in Tetrahedral and Square Planar Complexes:

   - Visual representation of the d-orbital splitting in tetrahedral and square planar geometries, showing the resulting electronic configurations.

 

[Include visuals to illustrate high-spin vs. low-spin arrangements and examples of different geometries affecting magnetic properties.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Determine the magnetic properties of [Fe(CN)\(_6\)]\(^{4-}\). (Fe is in the +2 oxidation state)

 

- Solution:

  1. Oxidation State of Fe: In [Fe(CN)\(_6\)]\(^{4-}\), the oxidation state of Fe is +2, so the electronic configuration is 3d\(^6\).

  2. Identify Ligand Field Strength: CN\(^-\) is a strong field ligand, which leads to large splitting energy (\(\Delta_o\)).

  3. Electron Configuration: With a strong field ligand, the complex is low-spin, with all six electrons paired in the \(t_{2g}\) orbitals.

  4. Magnetic Properties: Since there are no unpaired electrons, the complex is diamagnetic.

  - Answer: [Fe(CN)\(_6\)]\(^{4-}\) is diamagnetic.

 

Example Problem 2: Calculate the magnetic moment of [CoF\(_6\)]\(^{3-}\). (Co is in the +3 oxidation state)

 

- Solution:

  1. Oxidation State of Co: In [CoF\(_6\)]\(^{3-}\), the oxidation state of Co is +3, so the electronic configuration is 3d\(^6\).

  2. Identify Ligand Field Strength: F\(^-\) is a weak field ligand, which results in a high-spin configuration.

  3. Electron Configuration: In the high-spin state, there are 4 unpaired electrons.

  4. Calculate Magnetic Moment: \(\mu = \sqrt{n(n + 2)} = \sqrt{4(4 + 2)} = \sqrt{24} = 4.90 \, \mu_B\).

  - Answer: The magnetic moment of [CoF\(_6\)]\(^{3-}\) is 4.90 Bohr magnetons.

7. Common Tricks, Shortcuts, and Solving Techniques

- Use of Spectrochemical Series: Refer to the spectrochemical series to determine whether a ligand is strong field or weak field, which will help predict high-spin or low-spin configurations.

- Magnetic Moment Formula: Use \(\mu = \sqrt{n(n + 2)}\) to quickly calculate the magnetic moment based on the number of unpaired electrons.

8. Patterns in JEE Questions

JEE Advanced questions on magnetic properties of coordination compounds may involve:

- Predicting whether a complex is paramagnetic or diamagnetic.

- Calculating the magnetic moment using the number of unpaired electrons.

- Determining the spin state (high-spin or low-spin) based on ligand field strength.

9. Tips to Avoid Common Mistakes

- Misidentifying Spin State: Always consider the ligand field strength; weak field ligands lead to high-spin, while strong field ligands often lead to low-spin.

- Incorrect Magnetic Moment Calculation: Ensure that you correctly determine the number of unpaired electrons before using the magnetic moment formula.

10. Key Points to Remember for Revision

- Paramagnetism vs. Diamagnetism: Unpaired electrons lead to paramagnetism, while all paired electrons lead to diamagnetism.

- Magnetic Moment Calculation: Use \(\mu = \sqrt{n(n + 2)}\) Bohr magnetons, where \(n\) is the number of unpaired electrons.

- Effect of Ligands: Weak field ligands typically create high-spin complexes, while strong field ligands lead to low-spin configurations.

11. Real-World Applications and Cross-Chapter Links

- Magnetic Resonance: Paramagnetic coordination compounds are used in magnetic resonance imaging (MRI) as contrast agents.

- Catalysis: The magnetic properties of a complex can affect its behavior as a catalyst in various chemical reactions.

- Cross-Concept Connections: Links to crystal field theory, ligand field strength, and electronic configurations are essential for understanding magnetic properties.

Questions

Q 1. \([E D T A]^{4-}\) is a :;

(a) monodentate ligand;

(b) bidentate ligand;

(c) quadridentate ligand;

(d) hexadentate ligand;

Stability of coordination complexes


Stability of Coordination Complexes

1. Definition and Core Explanation

The stability of coordination complexes refers to the extent to which a complex can resist dissociation into its constituent ions or ligands. The stability of a coordination compound is influenced by various factors, including the nature of the metal ion, the ligand, and thermodynamic factors. Stability is important because it affects the reactivity, formation, and biological activity of the complex.

 

- Stability Constant (\(K_f\)): The stability of a complex is often expressed in terms of its formation constant (\(K_f\)), also called the stability constant. A larger \(K_f\) value indicates a more stable complex.

- Dissociation Constant (\(K_d\)): The dissociation constant (\(K_d\)) is the inverse of the formation constant. A lower \(K_d\) indicates higher stability.

- Thermodynamic and Kinetic Stability:

  - Thermodynamic Stability: Refers to the energetic favorability of the complex’s formation, often quantified using \(K_f\).

  - Kinetic Stability: Refers to the rate at which a complex forms or dissociates. A kinetically stable complex is one that forms or dissociates very slowly, regardless of its thermodynamic stability.

2. Factors Affecting Stability of Coordination Complexes

 

1. Nature of Metal Ion:

   - Charge on Metal Ion: Higher charges generally lead to stronger interactions between the metal and the ligands, increasing the stability of the complex.

   - Size of Metal Ion: Smaller metal ions with high charge-to-radius ratios tend to form more stable complexes.

 

2. Nature of Ligand:

   - Charge and Basicity: Ligands with higher negative charges and greater basicity tend to form more stable complexes.

   - Chelation Effect: Polydentate ligands (chelating ligands) form more stable complexes compared to monodentate ligands due to the chelating effect, which increases stability by forming ring structures.

 

3. Chelate Effect:

   - Complexes with chelating ligands are more stable due to the formation of five- or six-membered rings, which are entropically favored. This effect is quantified by the chelate stability constant.

 

4. Hard and Soft Acids and Bases (HSAB Theory):

   - Hard acids (like \(\text{Al}^{3+}\)) prefer to bond with hard bases (like \(\text{OH}^-\)), while soft acids (like \(\text{Pt}^{2+}\)) prefer soft bases (like \(\text{PPh}_3\)). Matching hardness/softness tends to increase stability.

 

5. Nature of the Solvent:

   - The solvent can also influence the stability of complexes. Polar solvents tend to stabilize ionic complexes, while nonpolar solvents can favor nonionic complexes.

3. Key Terms and Concepts

- Formation Constant (\(K_f\)): A measure of the stability of a complex; higher values indicate greater stability.

- Chelation: The process by which a polydentate ligand forms multiple bonds with a single metal ion, leading to increased stability.

- Hard and Soft Acids and Bases (HSAB): A concept used to predict the stability of complexes based on the hardness or softness of acids (metal ions) and bases (ligands).

4. Important Rules, Theorems, and Principles

- Chelate Effect: Polydentate ligands form more stable complexes compared to monodentate ligands due to entropic effects.

- Irving-Williams Series: A trend in the stability of metal complexes of divalent metal ions, generally observed as: Mn\(^2+\) < Fe\(^2+\) < Co\(^2+\) < Ni\(^2+\) < Cu\(^2+\) > Zn\(^2+\).

- HSAB Principle: Hard acids prefer to bind to hard bases, and soft acids prefer to bind to soft bases, leading to greater stability in the complex.

5. Illustrative Diagrams and Visuals

 

1. Chelate Effect:

   - Diagram illustrating the difference between a complex formed with a monodentate ligand and one formed with a bidentate ligand, emphasizing the ring structure formed by chelation.

 

2. Stability Constant Graph:

   - Graph showing the relationship between formation constants (\(K_f\)) for various metal-ligand complexes, demonstrating differences in stability.

 

3. HSAB Concept:

   - Visual representation of hard and soft acids and bases, with examples of each and the corresponding stability of complexes.

 

[Include visuals that demonstrate chelation, stability trends, and the HSAB concept to clarify how these factors influence complex stability.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Explain why [Co(en)\(_3\)]\(^{3+}\) is more stable than [Co(NH\(_3\))\(_6\)]\(^{3+}\).

 

- Solution:

  1. Chelate Effect: The en (ethylenediamine) ligand is bidentate, meaning it can form two bonds with the central cobalt ion, while NH\(_3\) is monodentate, forming only one bond.

  2. Stability Comparison: The chelate effect increases the stability of the complex with en compared to the complex with NH\(_3\) because the formation of ring structures is entropically favored.

  - Answer: [Co(en)\(_3\)]\(^{3+}\) is more stable due to the chelating effect of the en ligands, which leads to greater thermodynamic stability.

 

Example Problem 2: Determine which complex is more stable: [Fe(CN)\(_6\)]\(^{4-}\) or [Fe(H\(_2\)O)\(_6\)]\(^{2+}\).

 

- Solution:

  1. Ligand Field Strength: CN\(^-\) is a strong field ligand, while H\(_2\)O is a weak field ligand.

  2. Formation Constant: Strong field ligands like CN\(^-\) increase the crystal field splitting energy (\(\Delta\)), which generally leads to a more stable complex.

  - Answer: [Fe(CN)\(_6\)]\(^{4-}\) is more stable than [Fe(H\(_2\)O)\(_6\)]\(^{2+}\) due to the strong field effect of the CN\(^-\) ligands.

 

7. Common Tricks, Shortcuts, and Solving Techniques

- Chelate Effect Shortcut: Complexes with polydentate ligands are almost always more stable due to the chelate effect.

- HSAB Matching: Remember to match hard acids with hard bases and soft acids with soft bases to predict higher stability.

8. Patterns in JEE Questions

JEE Advanced questions on the stability of coordination complexes may involve:

- Comparing the stability of complexes with different ligands.

- Using the Irving-Williams series to predict relative stability.

- Explaining the chelating effect and how it influences the stability of metal complexes.

9. Tips to Avoid Common Mistakes

- Confusing Chelate and Macrocyclic Effects: Remember that the chelate effect refers to the increased stability due to multiple bonds from a single ligand, while the macrocyclic effect refers to even greater stability from cyclic polydentate ligands.

- Ignoring Ligand Field Strength: Always consider the ligand field strength when comparing the stability of complexes; strong field ligands tend to create more stable complexes.

10. Key Points to Remember for Revision

- Formation Constant (\(K_f\)): A higher value indicates greater stability.

- Chelate Effect: Complexes with chelating ligands are more stable due to entropic favorability.

- HSAB Theory: Hard acids prefer hard bases, and soft acids prefer soft bases, leading to greater stability in coordination compounds.

11. Real-World Applications and Cross-Chapter Links

- Biological Chelates: EDTA is used in medicine to chelate metal ions in cases of heavy metal poisoning, demonstrating the stability imparted by chelation.

- Catalysis: The stability of metal complexes plays a significant role in their catalytic activity, as more stable complexes are often used as catalysts in industrial reactions.

- Cross-Concept Connections: Links to ligand field theory, hard and soft acids and bases (HSAB), and entropy changes are crucial for understanding the stability of coordination complexes.

Questions

Q 1. The compound having the lowest oxidation state of iron is:;

(a) \(\mathrm{K}_{4} \mathrm{Fe}(\mathrm{CN})_{6}\);

(b) \(\mathrm{K}_{2} \mathrm{FeO}_{4}\);

(c) \(\mathrm{Fe}_{2} \mathrm{O}_{3}\);

(d) \(\mathrm{Fe}(\mathrm{CO})_{5}\);

Applications of coordination compounds in industry and medicine


Applications of Coordination Compounds in Industry and Medicine

1. Definition and Core Explanation

Coordination compounds, also known as complexes, consist of a central metal atom or ion bonded to one or more ligands via coordinate covalent bonds. These compounds play a crucial role in a wide array of industrial and medical applications due to their unique chemical properties such as variable oxidation states, complex formation, and catalytic activity. Coordination compounds exhibit specific binding, color, stability, and reactivity, which makes them suitable for several specialized uses.

2. Industrial Applications of Coordination Compounds

 

1. Catalysis:

   - Catalytic Converters: Coordination compounds of platinum (Pt), palladium (Pd), and rhodium (Rh) are used as catalysts in catalytic converters to reduce harmful emissions in automobiles by converting CO, NO\(_x\), and hydrocarbons into less harmful gases like CO\(_2\) and N\(_2\).

   - Polymerization Catalysts: Ziegler-Natta catalysts, which are titanium-based coordination complexes, are used in the production of polyethylene and polypropylene. These catalysts help control the structure and properties of polymers during polymerization.

 

2. Electroplating and Extraction:

   - Electroplating: Coordination complexes, such as [Ni(CN)\(_4\)]\(^{2-}\), are used in the electroplating of metals like nickel to provide a corrosion-resistant surface to metal products.

   - Metal Extraction: Coordination compounds like [Au(CN)\(_2\)]\(^{-}\) are used in the cyanide process to extract gold and silver from their ores.

 

3. Pigments and Dyes:

   - Colored Pigments: Coordination compounds are used to produce a wide variety of pigments. For example, Prussian Blue, a complex of iron, is used as a pigment in paints.

   - Textile Dyes: Complexes of chromium are used in the textile industry to produce dyes with vibrant colors and good wash fastness.

 

4. Water Softening and Treatment:

   - EDTA (Ethylenediaminetetraacetic Acid): EDTA, a common chelating agent, is used to remove metal ions from hard water in water softening processes. EDTA forms stable complexes with metal ions like Ca\(^2+\) and Mg\(^2+\), effectively reducing water hardness.

3. Medical Applications of Coordination Compounds

 

1. Chemotherapy:

   - Cisplatin and Related Drugs: Cisplatin, [PtCl\(_2\)(NH\(_3\))\(_2\)], is a coordination compound used in cancer treatment. It works by binding to the DNA in cancer cells, causing cross-linking that inhibits DNA replication and ultimately leads to cell death. Newer analogs like carboplatin have also been developed to reduce side effects while retaining efficacy.

 

2. Diagnostic Agents:

   - MRI Contrast Agents: Gadolinium-based complexes, such as [Gd(DTPA)]\(^2-\), are used as contrast agents in magnetic resonance imaging (MRI). Gadolinium ions are toxic, but in the complexed form, they are safe for use and help improve the contrast in MRI images, providing clearer details of soft tissues.

 

3. Metal Ion Sequestration and Poisoning Treatment:

   - Chelation Therapy: Coordination compounds like EDTA are used in chelation therapy to treat heavy metal poisoning, such as lead or mercury poisoning. EDTA forms stable complexes with these toxic metals, allowing them to be excreted safely from the body.

 

4. Oxygen Transport and Storage:

   - Hemoglobin and Myoglobin: The coordination compound heme, found in hemoglobin and myoglobin, plays a vital role in the transport and storage of oxygen in the body. Iron (Fe) in heme forms coordination bonds with oxygen, facilitating oxygen transport in the bloodstream.

 

5. Antimicrobial and Antibacterial Agents:

   - Silver Complexes: Silver coordination compounds, such as silver sulfadiazine, are used as antibacterial agents in the treatment of burns. These complexes release silver ions slowly, which help kill bacteria and prevent infections.

 

---

 

 4. Key Terms and Concepts

- Chelating Agent: A ligand that can form multiple bonds with a single metal ion, increasing the stability of the coordination complex.

- Cisplatin: A coordination compound of platinum used in chemotherapy to treat cancer by binding to DNA and inhibiting replication.

- MRI Contrast Agent: A complex that enhances the quality of MRI images by altering the magnetic properties of nearby water molecules.

5. Illustrative Diagrams and Visuals

 

1. Cisplatin Mechanism of Action:

   - Diagram showing cisplatin binding to DNA, forming cross-links that prevent DNA replication and ultimately lead to cell apoptosis.

 

2. Chelation of Metal Ions by EDTA:

   - Visual representation of EDTA chelating metal ions like Ca\(^2+\), demonstrating how it effectively sequesters and removes metal ions from a solution.

 

3. MRI Contrast Agent:

   - Diagram of a gadolinium-based MRI contrast agent and its effect on imaging, highlighting the interaction of the complex with water molecules.

 

[Include visuals that illustrate the action mechanisms of cisplatin, EDTA chelation, and MRI contrast agents.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Explain why EDTA is used in water softening.

 

- Solution:

  1. Chelation Property: EDTA is a hexadentate ligand that can form multiple bonds with metal ions, such as Ca\(^2+\) and Mg\(^2+\), which are responsible for water hardness.

  2. Complex Formation: By forming stable complexes with Ca\(^2+\) and Mg\(^2+\), EDTA effectively removes these ions from the water, reducing hardness.

  - Answer: EDTA is used in water softening because it forms stable complexes with Ca\(^2+\) and Mg\(^2+\), removing these ions from hard water.

 

Example Problem 2: Describe how cisplatin is effective in cancer treatment.

 

- Solution:

  1. DNA Binding: Cisplatin forms coordination bonds with guanine bases in DNA, causing cross-linking that interferes with DNA replication.

  2. Apoptosis: The cross-linking prevents the cell from replicating properly, ultimately triggering apoptosis (programmed cell death).

  - Answer: Cisplatin is effective in cancer treatment because it binds to DNA, causing cross-links that inhibit replication and lead to apoptosis.

7. Common Tricks, Shortcuts, and Solving Techniques

- Chelating Agents in Medicine: Remember that chelating agents are often used for metal ion sequestration in both industrial and medical applications, such as treating heavy metal poisoning.

- Catalyst Identification: Coordination complexes of platinum, palladium, and rhodium are commonly used as catalysts in industrial processes, such as automotive exhaust treatment.

8. Patterns in JEE Questions

JEE Advanced questions on the applications of coordination compounds may involve:

- Explaining the mechanism of action of complexes like cisplatin in cancer therapy.

- Discussing the role of coordination compounds in catalysis and other industrial processes.

- Identifying chelating agents and explaining their use in water treatment or metal ion sequestration.

9. Tips to Avoid Common Mistakes

- Mixing Up Types of Coordination Compounds: Ensure you clearly understand the different roles of coordination compounds in industry (e.g., catalysis) versus medicine (e.g., chelation therapy).

- Incomplete Mechanism Explanation: When explaining mechanisms (such as cisplatin's action), include both the binding aspect and its biological effect, like inhibiting DNA replication.

10. Key Points to Remember for Revision

- Catalysis: Coordination compounds are used extensively as catalysts in industrial processes, such as polymerization and automotive exhaust treatment.

- Medical Uses: Compounds like cisplatin are crucial for chemotherapy, while EDTA is used in treating heavy metal poisoning.

- Chelating Agents: Ligands that can form multiple bonds with metal ions, increasing the stability and effectiveness of coordination compounds in different applications.

11. Real-World Applications and Cross-Chapter Links

- Cancer Treatment: Cisplatin and its derivatives are some of the most important drugs for chemotherapy, illustrating the biological importance of coordination chemistry.

- Water Treatment: The use of EDTA in water softening and chelating applications is an important industrial use of coordination compounds.

- Cross-Concept Connections: Links to bonding in coordination compounds, ligand field theory, and thermodynamics are crucial for understanding the behavior and applications of these complexes.

Questions

Q 1. The coordination number and the oxidation state of the element ' \(E\) ' in the complex \(\left[\mathrm{E}(\mathrm{en})_{2}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\right] \mathrm{NO}_{2}\) (where (en) is ethylene diamine) are, respectively,;

(a) 6 and 2;

(b) 4 and 2;

(c) 4 and 3;

(d) 6 and 3;

General properties and principles of coordination compounds, bonding, and applications


General Properties and Principles of Coordination Compounds, Bonding, and Applications

1. Definition and Core Explanation

Coordination compounds are complex chemical entities that consist of a central metal atom or ion surrounded by molecules or ions known as ligands. Ligands are atoms, ions, or molecules that donate a pair of electrons to the metal center, forming a coordinate bond. Coordination compounds are also known as complexes, and they exhibit properties that differ significantly from the properties of the central metal and ligands individually.

 

Bonding in Coordination Compounds involves:

- Coordinate Bonds: Bonds formed between the metal and ligands, where the ligand donates a lone pair of electrons to the metal.

- Ligands: These can be neutral (e.g., water, ammonia) or anionic (e.g., halides, cyanide), and they can be classified based on the number of donor atoms, such as monodentate, bidentate, or polydentate ligands.

 

The general importance of coordination compounds lies in their structural diversity, stability, and wide range of applications in both industrial processes and medical fields.

2. Properties of Coordination Compounds

 

1. Color:

   - Many coordination compounds exhibit vivid colors due to d-d transitions or charge transfer between the metal and ligands.

   - The color arises because the energy difference between split d-orbitals corresponds to the energy of visible light, leading to the absorption of specific wavelengths and the appearance of color.

 

2. Variable Oxidation States:

   - The central metal atom in coordination compounds can exhibit multiple oxidation states, allowing for a wide range of chemical reactions and complex formation.

   - For instance, iron can form complexes in +2 or +3 oxidation states, and cobalt can exist in +2 or +3 states.

 

3. Complex Ion Formation:

   - Coordination compounds can form complex ions, which are ions that contain a central metal bonded to one or more ligands. These complexes are often charged and can participate in a wide range of chemical reactions.

 

4. Magnetic Properties:

   - Depending on the number of unpaired electrons in the d-orbitals of the central metal, coordination compounds can be paramagnetic (with unpaired electrons) or diamagnetic (with no unpaired electrons).

 

5. Stability and Formation Constant (\(K_f\)):

   - The stability of a coordination compound is measured by its formation constant (\(K_f\)). A higher formation constant indicates a more stable complex. Factors affecting stability include the nature of the ligand, metal ion, and chelation.

3. Key Principles of Bonding in Coordination Compounds

 

1. Werner's Theory:

   - Alfred Werner, the father of coordination chemistry, proposed that metal atoms can exhibit primary valency (oxidation state) and secondary valency (coordination number).

   - According to Werner’s theory, the primary valency is ionizable, while the secondary valency is satisfied by ligands directly bonded to the metal, resulting in specific coordination geometries.

 

2. Valence Bond Theory (VBT):

   - VBT explains the bonding in coordination compounds by assuming that the metal atom hybridizes its orbitals to form bonding orbitals that accept electron pairs from ligands.

   - For instance, an octahedral complex like [Co(NH\(_3\))\(_6\)]\(^{3+}\) forms sp\(^3\)d\(^2\) hybridized orbitals to accommodate the six ligands.

 

3. Crystal Field Theory (CFT):

   - CFT describes the interaction between the metal ion and ligands as an electrostatic interaction, leading to the splitting of d-orbitals into two different energy levels.

   - In an octahedral field, the d-orbitals split into \(t_{2g}\) (lower energy) and \(e_g\) (higher energy) orbitals, leading to d-d transitions and the unique properties of the complex, such as color and magnetism.

 

4. Chelate Effect:

   - Ligands that have multiple donor atoms can form ring-like structures around the metal ion, called chelates. Chelation increases the stability of the complex due to the entropy gain and multiple bonding interactions.

   - A classic example is EDTA, a hexadentate ligand that forms highly stable complexes with many metal ions.

4. Important Rules, Theorems, and Principles

- Werner’s Theory: Differentiates between primary (oxidation state) and secondary (coordination number) valencies.

- Chelate Effect: Explains the enhanced stability of complexes with polydentate ligands due to multiple points of attachment.

- Crystal Field Splitting: The splitting of d-orbitals into two different sets of energy levels in the presence of ligands, determining the properties of the coordination compound.

5. Illustrative Diagrams and Visuals

 

1. Crystal Field Splitting:

   - Diagram showing d-orbital splitting in an octahedral coordination compound, illustrating the difference between \(t_{2g}\) and \(e_g\) energy levels.

 

2. Chelate Effect:

   - Visual representation of a bidentate ligand, such as ethylenediamine, forming a chelate ring around a central metal ion, illustrating the stability provided by multiple bonds.

 

3. Werner’s Coordination Structures:

   - Diagram depicting the difference between primary valency and secondary valency, as proposed by Alfred Werner, using coordination complexes as examples.

 

[Include visuals to illustrate concepts like crystal field splitting, chelate effect, and Werner’s coordination structures.]

6. Sample Problems and Step-by-Step Solutions

 

Example Problem 1: Explain why [Fe(CN)\(_6\)]\(^{4-}\) is more stable than [Fe(H\(_2\)O)\(_6\)]\(^{2+}\).

 

- Solution:

  1. Ligand Strength: CN\(^-\) is a strong field ligand, which leads to greater crystal field splitting and stabilization of the complex.

  2. Chelation and Stability: The formation constant (\(K_f\)) for [Fe(CN)\(_6\)]\(^{4-}\) is much larger than for [Fe(H\(_2\)O)\(_6\)]\(^{2+}\), indicating a more stable complex.

  - Answer: The presence of strong field ligands like CN\(^-\) makes [Fe(CN)\(_6\)]\(^{4-}\) more stable compared to [Fe(H\(_2\)O)\(_6\)]\(^{2+}\).

 

Example Problem 2: Describe the type of hybridization in [Ni(CO)\(_4\)] and its geometry.

 

- Solution:

  1. Ligand Type: CO is a neutral ligand and forms coordinate bonds with Ni.

  2. Hybridization: To accommodate four ligands, Ni undergoes sp\(^3\) hybridization.

  3. Geometry: The resulting complex has a tetrahedral geometry.

  - Answer: In [Ni(CO)\(_4\)], sp\(^3\) hybridization occurs, resulting in a tetrahedral geometry.

7. Common Tricks, Shortcuts, and Solving Techniques

- Ligand Field Strength: Remember that strong field ligands like CN\(^-\) and CO often lead to low-spin configurations, whereas weak field ligands like H\(_2\)O and F\(^-\) lead to high-spin configurations.

- Werner’s Primary vs. Secondary Valency: The primary valency corresponds to the oxidation state, while the secondary valency corresponds to the coordination number, determining the number of ligands.

8. Patterns in JEE Questions

JEE Advanced questions on coordination compounds may involve:

- Predicting the geometry of a complex based on the hybridization and coordination number.

- Using crystal field theory to determine the color and magnetism of a complex.

- Explaining the stability of complexes using the chelate effect or ligand field strength.

9. Tips to Avoid Common Mistakes

- Confusing Coordination Number with Oxidation State: Remember that the coordination number refers to the number of ligands attached to the metal, whereas the oxidation state refers to the charge of the metal after considering all bonded ligands.

- Incorrect Ligand Classification: Ligands like EDTA are polydentate, meaning they can form multiple bonds. Misclassifying ligands can lead to incorrect

Questions

Q 1. Some salts although containing two different metallic elements give test for only one of them in solution Such salts are;

(a) complex;

(b) double salts;

(c) normal salts;

(d) None of these;

Q 2. Coordination number of \(\mathrm{Ni}\) in \(\left[\mathrm{Ni}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{4}\) is;

(a) 3;

(b) 6;

(c) 4;

(d) 5;

Q 3. According to Lewis, the ligands are;

(a) acidic in nature;

(b) basic in nature;

(c) some are acidic and others are basic;

(d) neither acidic nor basic;

Q 4. Ligand in a complex salt are;

(a) anions linked by coordinate bonds to a central metal atom or ion;

(b) cations linked by coordinate bonds to a central metal or ion;

(c) molecules linked by coordinate bonds to a central metal or ion;

(d) ions or molecules linked by coordinate bonds to a central atom or ion;

Q 5. The ligand \(\mathrm{N}\left(\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\right)_{3}\) is;

(a) tridentate;

(b) pentadentate;

(c) tetradentate;

(d) bidentate;

Q 6. An example of ambidentate ligand is;

(a) Ammine;

(b) Aquo;

(c) Chloro;

(d) Thiocyanato;

Q 7. Which of the following does not form a chelate?;

(a) EDTA;

(b) Oxalate;

(c) Pyridine;

(d) Ethylenediamine;

Q 8. A bidenate ligand always;

(a) has bonds formed to two metals ions;

(b) has a charge of +2 or -2;

(c) forms complex ions with a charge of +2 or -2;

(d) has two donor atoms forming simultaneously two sigma \((\sigma)\) bonds.;

Q 9. An ambident ligand is one which;

(a) is linked to the metal atom through two donor atoms;

(b) has two donor atoms, but only one of them has the capacity to form a coordinate bond [or a sigma ( \(\sigma\) ) bond];

(c) has two donor atoms, but either of two can form a coordinate bond;

(d) forms chelate rings.;

Q 10. \(\mathrm{NH}_{2}-\mathrm{NH}_{2}\) serves as;

(a) Monodentate ligand;

(b) Chelating ligand;

(c) Bridging ligand;

(d) Both (a) and (c);

Topics

Werner's theory of coordination compounds

Primary and secondary valency in coordination compounds

Primary valency and oxidation states in coordination complexes

Coordination number and structure of complexes

Precipitation reactions in coordination compounds

Nomenclature of coordination compounds

Oxidation state determination in complexes

Isomerism in coordination compounds

Geometrical isomerism in complexes

Optical isomerism in coordination complexes

Crystal field theory and splitting of d-orbitals

Ligand field strength and spectrochemical series

Bonding in metal carbonyls

Magnetic properties of coordination compounds

Stability of coordination complexes

Applications of coordination compounds in industry and medicine

General properties and principles of coordination compounds, bonding, and applications

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